I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN
(Equation 29)
∠
I
50s
= 0º
frequency of
I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN
(Equation 30)
∠
I
tfs
= 0º
frequency of
I
tf
= 50 Hz
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%) ) are
according to the injected quantities and that ROTORANG is close to 3.14 rad. For
this particular injection the service values are:
•
VOLTAGE = 10.74 kV
•
CURRENT = 20918 A
•
R = 7.37%
•
X = 53.40%
•
ROTORANG = -3.09 rad
Note that these values identify a point inside the lens characteristic, in the zone 2,
that is close to the point RE. The START is issued, but no TRIP is performed.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance,
that is, a point in the plane R-X which is far away from the lens characteristic.
Define the following three-phase symmetrical quantities (the phase angle is
related to phase L1):
V
V
V
V
V
ts
t FwdZ
VT s
VT p
=
×
×
=
×
×
=
0 9
0 9 11931
0 1
13 8
77 81
.
.
.
.
.
,
,
,
EQUATION14063 V1 EN
(Equation 31)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN
(Equation 32)
frequency of V
ts
= 50 Hz
I
50s
= 0 A
I
tfs
= 0 A
•
State 2: main test step.
Section 12
1MRK502053-UEN B
Testing functionality by secondary injection
130
Generator protection REG670 2.0 IEC
Commissioning manual
Summary of Contents for REG670 2.0 IEC
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