frequency of V
ts
= 50 Hz
I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN
(Equation 49)
∠
I
50s
= 0º
frequency of
I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN
(Equation 50)
∠
I
tfs
= 0º
frequency of
I
tf
= 50 Hz
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are
according to the injected quantities and that ROTORANG is close to 3.14 rad. For
this particular injection the service values are:
•
VOLTAGE = 1.29 kV
•
CURRENT = 20918 A
•
R = 0.89%
•
X=6.42%
•
ROTORANG = -3.04 rad
Note that these values identify a point inside the lens characteristic in zone 1, that
is close to the boundary between zone 1 and zone 2. The START is issued, but no
TRIP is performed.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance,
that is a point in the plane R-X which is far away from the lens characteristic.
Define the following three-phase symmetrical quantities (the phase angle is
related to phase L1):
V
V
V
V
V
ts
t RZ
VT s
VT p
=
×
×
=
×
×
=
0 9
0 9 1435
0 1
13 8
9 36
1
.
.
.
.
.
,
,
,
EQUATION14066 V1 EN
(Equation 51)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN
(Equation 52)
frequency of V
ts
= 50 Hz
I
50s
= 0 A
Section 12
1MRK502053-UEN B
Testing functionality by secondary injection
134
Generator protection REG670 2.0 IEC
Commissioning manual
Summary of Contents for REG670 2.0 IEC
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