background image

036-21603-002 Rev. A (1004)

6

Unitary Products Group

FILTER PERFORMANCE

The airflow capacity data published in the “Blower Perfor-
mance” table listed above represents blower performance
WITHOUT filters. To determine the approximate blower per-
formance of the system, apply the filter drop value for the fil-
ter being used or select an appropriate value from the “Filter
Performance” table shown below.

NOTE: 

The filter pressure drop values in the “Filter Perfor-

mance” table shown below are typical values for the type of 
filter listed and should only be used as a guideline. Actual 
pressure drop ratings for each filter type vary between filter 
manufacturer.

* Washable fiber are the type supplied with furnace (if supplied).

APPLYING FILTER PRESSURE DROP TO 
DETERMINE SYSTEM AIRFLOW

To determine the approximate airflow of the unit with a filter in place,
follow the steps below:

1.

Select the filter type.

2.

Select the number of return air openings or calculate the return
opening size in square inches to determine the proper filter
pressure drop.

3.

Determine the External System Static Pressure (ESP) without
the filter.

4.

Select a filter pressure drop from the table based upon the num-
ber of return air openings or return air opening size and add to
the ESP from Step 3 to determine the total system static.

5.

If total system static matches a ESP value in the airflow table
(i.e. 0.20 w.c. (50 Pa), 0.60 w.c. (150 Pa), etc,) the system air-
flow corresponds to the intersection of the ESP column and
Model/Blower Speed row.

6.

If the total system static falls between ESP values in the table
(i.e. 0.58 w.c. (144 Pa), 0.75 w.c. (187 Pa), etc.), the static pres-
sure may be rounded to the nearest value in the table determin-
ing the airflow using Step 5 or calculate the airflow by using the
following example.

Example: For a 130,000 BTUH (38.06 kW) furnace with 2 return
openings and operating on high-speed blower, it is found that total
system static is 0.58” w.c. To determine the system airflow, complete
the following steps:
Obtain the airflow values at 0.50 w.c. (125 Pa) & 0.60 w.c. (150 Pa)
ESP.

Airflow @ 0.50”: 2125 CFM (60.17 m

3

/min)

Airflow @ 0.60”: 2035 CFM (57.62 m

3

/min)

Subtract the airflow @ 0.50 w.c. (125 Pa) from the airflow @ 0.60
w.c. (150 Pa) to obtain airflow difference.

2035 - 2125 = -90 CFM (2.55 m

3

/min)

Subtract the total system static from 0.50 w.c. (125 Pa) and divide
this difference by the difference in ESP values in the table, 0.60 w.c.
(150 Pa) - 0.50 w.c. (125 Pa), to obtain a percentage.
(0.58 - 0.50) / (0.60 - 0.50) = 0.8
Multiply percentage by airflow difference to obtain airflow reduction.
(0.8) X (-90) = -72
Subtract airflow reduction value to airflow @ 0.50 w.c. (125 Pa) to
obtain actual airflow @ 0.58 inwc (144 Pa) ESP.
2125 - 72 = 2053

FILTER PERFORMANCE - PRESSURE DROP INCHES W.C.

Airflow 

Range 

Minimum Opening Size

Filter Type 

Disposable WASHABLE 

FIBER*  Pleated 

1 Opening 

2 Openings 

1 Opening

2 Openings

1 Opening

2 Openings

1 Opening

2 Openings

CFM

In³

In³

inwc

inwc

inwc

inwc

inwc

inwc

0 - 750 

230

0.01

0.01

0.15

751 - 1000

330

0.05

0.05

0.2

1001 - 1250

330

0.1

0.1

0.2

1251 - 1500

330

0.1

0.1

0.25

1501 - 1750

380

658

0.15

0.09

0.14

0.08

0.3

0.17

1751 - 2000

380

658

0.19

0.11

0.18

0.1

0.3

0.17

2001 & Above

463

658

0.19

0.11

0.18

0.1

0.3

0.17

UNIT CLEARANCES TO COMBUSTIBLES (ALL DIMENSIONS IN INCHES)
(ALL SURFACES IDENTIFIED WITH THE UNIT IN AN UPFLOW CONFIGURATION)

APPLICATION

TOP FRONT REAR LEFT SIDE RIGHT SIDE

FLUE

FLOOR/ 

BOTTOM

CLOSET ALCOVE ATTIC

LINE 

CONTACT

In.

In.

In.

In. (cm)

In. (cm)

In. (cm)

UPFLOW

1

6

0

0

3

1

6

COMBUSTIBLE

YES

YES

YES

NO

UPFLOW B-VENT

1

3

0

0

1

COMBUSTIBLE

YES

YES

YES

NO

HORIZONTAL

3

2

6

0

1 0

6

COMBUSTIBLE

NO

YES

YES

YES

3

HORIZONTAL B-VENT

0

3

0

1

0

1

COMBUSTIBLE

NO

YES

YES

YES

3

1

14-1/2” cabinet models only. All other units “0” clearance.

2

14-1/2” cabinet left airflow applications only. All other units and right hand airflow applications “0” clearance.

3

Line contact only permitted between lines formed by the intersection of the rear panel and side panel (top in horizontal position) of the furnace jacket and building joists, studs or 
framing.

Summary of Contents for Echelon FC8T

Page 1: ... year heat exchanger warranty on commercial applica tions 5 year limited parts warranty FEATURES Two stage heating operation includes Two stage gas valve Two stage inducer operation Provides increased comfort level very quiet unit oper ation Adjustable delay timer allows two stage operation with single stage thermostat Compact easy to install ideal height 40 cabinet Blower off delay for cooling SE...

Page 2: ...1 8 10 1 8 F L C8T080B16UH11 64 48 1600 B 17 1 2 16 1 4 13 1 8 11 5 8 FC8T100B12UH11 80 53 1200 B 17 1 2 16 1 4 13 1 8 11 5 8 F L C8T100C20UH11 80 53 2000 C 21 19 3 4 16 5 8 13 3 8 FC8T120C16UH11 96 64 1600 C 21 19 3 4 16 5 8 13 3 8 F L C8T120C20UH11 96 64 2000 C 21 19 3 4 16 5 8 13 3 8 HORIZONTAL VENTING MUST USE FIELDS CONTROL MODELS SWG 4Y OR TJERENLAND MODEL GPAK JT FIELD SUPPLIED POWER VENTIN...

Page 3: ...14 1 2 80 0 25 55 165 F L C8T080A12UH11 64 48 1200 14 1 2 80 0 30 60 175 F L C8T080B16UH11 64 48 1600 17 1 2 80 0 25 55 160 FC8T100B12UH11 80 53 1200 17 1 2 80 0 25 55 170 F L C8T100C20UH11 80 53 2000 21 80 0 25 55 160 FC8T120C16UH11 96 64 1600 21 80 0 25 55 180 F L C8T120C20UH11 96 64 2000 21 80 0 25 55 170 Model Output Blower Blower Size Total Unit Max Over current Size awg 75 ft protect Min Wir...

Page 4: ...0 F L C8T080B16UH11 High 1850 1820 1790 1750 1690 1630 1570 1500 1430 1330 Medium 1470 1450 1440 1430 1390 1360 1310 1270 1220 1150 Low 1260 1260 1260 1260 1250 1200 1150 1110 1070 1010 FC8T100B12UH11 High 1700 1620 1560 1480 1390 1300 1210 1110 970 820 Medium High 1430 1400 1350 1300 1230 1160 1080 980 870 710 Medium Low 1180 1170 1160 1130 1080 1030 1000 860 750 510 Low 950 950 930 920 880 840 7...

Page 5: ...0 Low 1220 1230 1230 1230 1200 1190 1170 1160 1110 1050 FC8T100B12UH11 High 1780 1710 1640 1560 1490 1390 1290 1180 1030 820 Medium High 1430 1410 1370 1340 1280 1220 1140 1040 890 730 Medium Low 1140 1170 1150 1120 1080 1040 970 890 760 630 Low 920 940 950 940 920 890 850 770 660 560 F L C8T100C20UH11 High 2770 2670 2610 2540 2450 2340 2210 2070 1890 1730 Medium High 2120 2060 2030 2000 1950 1880...

Page 6: ...hat total system static is 0 58 w c To determine the system airflow complete the following steps Obtain the airflow values at 0 50 w c 125 Pa 0 60 w c 150 Pa ESP Airflow 0 50 2125 CFM 60 17 m3 min Airflow 0 60 2035 CFM 57 62 m3 min Subtract the airflow 0 50 w c 125 Pa from the airflow 0 60 w c 150 Pa to obtain airflow difference 2035 2125 90 CFM 2 55 m3 min Subtract the total system static from 0 ...

Page 7: ...WITCHES Used to convert units for operation at altitudes from 4 500 ft to 10 000 ft Input MBH Output MBH 2 000 Ft to 5 500 Ft 5 500 Ft to 0 000 Ft 40 32 1PS0301 1PS0301 60 48 1PS0301 1PS0301 80 64 1PS0302 1PS0302 100 80 1PS0312 1PS0311 115 92 1PS0312 1PS0311 130 104 1PS0312 1PS0311 FIELD INSTALLED ACCESSORIES ELECTRICAL MODEL NO DESCRIPTION USED WITH 2ET0770010124 THERMOSTAT Two stage Heat Cool de...

Page 8: ...e without notice Printed in U S A 036 21603 002 Rev A 1004 Copyright by York International Corp 2004 All rights reserved Supersedes 036 21603 001 Rev B 0904 Unitary 5005 Norman Products York OK Group Drive 73069 NOTES ...

Reviews: