GE Multilin
F60 Feeder Protection System
D-1
APPENDIX D
D.1 IEC 60870-5-103
D
APPENDIX D IEC 60870-5-103 COMMUNICATIONSD.1IEC 60870-5-103
D.1.1 OVERVIEW
IEC 60870-5-103 is defined as a companion standard for the informative element of the protection equipment. IEC 60870-
5-103 defines communication for a serial, unbalanced link only. Communication speeds are defined as either 9600 or
19200 baud.
This manual assumes basic knowledge of the IEC 60870-5-103 protocol and the standard IEC 60870 documents relating to
the protocol.
Standard IEC 60870 documents relating to IEC 60870-5-103:
•
IEC 60870-5-1 Transmission frame formats
•
IEC 60870-5-2 Link transmission procedures
•
IEC 60870-5-3 General structure of application data
•
IEC 60870-5-4 Definition and coding of application information elements
•
IEC 60870-5-5 Basic application functions
•
IEC 60870-5-6 Conformance testing guidelines
An IEC 60870-5-103 device is required to provide an interoperability table. Interoperability means that any required applica-
tion data in the device, which can be coded into an IEC 60870-5-103 data type, can be mapped into the IEC 60870-5-103
address space. This data is recognized by any IEC 60870-5-103 master.
D.1.2 FACTOR AND OFFSET CALCULATION TO TRANSMIT MEASURAND
The general formula for the transmitted value is Xt = a * X + b
where X is the measurand, a is the multiplication factor, b is the offset and Xt is the value transmitted.
The conditions for determining a and b, when the values exceed the range are:
4096 = a*Xmax + b (Xmax is the maximum value for the measurand)
-4095 =a*Xmin + b (Xmin is the minimum value for the measurand)
By solving the above system of equations for a and b, we find that:
a = 8191 / (Xmax - Xmin)
b = -4096 * (Xmax + Xmin) / (Xmax - Xmin)
So
Xt = 8191/(Xmax - Xmin)) * X - 4096 * (Xmax + Xmin) / (Xmax - Xmin)
We may further simplify the above formula for situations where:
1)
Xmin = -Xmax (positive and negative values) :
Xt = (8191/2*Xmax) * X
a = 4096/Xmax
b = 0
2)
If Xmin = 0 (only positive values)
Xt = (8191/Xmax) * X - 4096
a = 2 * 4096/Xmax
b = -4096
To calculate Xmax, one needs to know the rated value for the specific type of measurand.
Xmax = 2.4 * Xrated
Summary of Contents for F60
Page 10: ...x F60 Feeder Protection System GE Multilin TABLE OF CONTENTS ...
Page 30: ...1 20 F60 Feeder Protection System GE Multilin 1 5 USING THE RELAY 1 GETTING STARTED 1 ...
Page 138: ...4 28 F60 Feeder Protection System GE Multilin 4 2 FACEPLATE INTERFACE 4 HUMAN INTERFACES 4 ...
Page 454: ...5 316 F60 Feeder Protection System GE Multilin 5 10 TESTING 5 SETTINGS 5 ...
Page 500: ...7 14 F60 Feeder Protection System GE Multilin 7 1 COMMANDS 7 COMMANDS AND TARGETS 7 ...
Page 508: ...8 8 F60 Feeder Protection System GE Multilin 8 2 FAULT LOCATOR 8 THEORY OF OPERATION 8 ...
Page 522: ...10 12 F60 Feeder Protection System GE Multilin 10 6 DISPOSAL 10 MAINTENANCE 10 ...
Page 660: ...B 116 F60 Feeder Protection System GE Multilin B 4 MEMORY MAPPING APPENDIX B B ...
Page 706: ...E 10 F60 Feeder Protection System GE Multilin E 1 IEC 60870 5 104 APPENDIX E E ...
Page 718: ...F 12 F60 Feeder Protection System GE Multilin F 2 DNP POINT LISTS APPENDIX F F ...
Page 728: ...H 8 F60 Feeder Protection System GE Multilin H 2 ABBREVIATIONS APPENDIX H H Z Impedance Zone ...
Page 730: ...H 10 F60 Feeder Protection System GE Multilin H 3 WARRANTY APPENDIX H H ...