136 Section 11: Calculating With Complex Numbers
Keystrokes
Display
2
´
}
0.0000
2
i
. Display shows real part.
8
“
v
-8.0000
6
´
V
-8.0000
-8 + 6
i
.
3
Y
352.0000
(-8 + 6
i
)
3
.
*
-1.872.0000
2
i
(-8 + 6
i
)
3
.
4
v
4.0000
5
¤
2.2361
2
“
*
-4.4721
5
2
.
´
V
4.0000
i
5
2
4
.
÷
-295.4551
i
i
i
5
2
-
4
3
)
6
(-8
2
.
2
v
5
¤
2.2361
4
“
*
-8.9443
´
V
2.0000
i
5
4
2
.
÷
9.3982
Real part of result.
´
%
-35.1344
Answer: 9.3982 -35.1344
i
.
9.3982
2. Write a program to evaluate the function
3
5
1
2
z
z
ω
for different
values of
z.
(
ω
represents a linear fractional transformation, a class of
conformal mappings.) Evaluate
ω
for
z
= l+2
i
.
(Answer: 0.3902 + 0.0122
i
. One possible keystroke sequence is:
´
b
A
v v
2
*
1
+
®
5
*
3
+
÷
¦
´
}
|
n
.)
3. Try your hand at a complex polynomial and rework the example on
page 80. You can use the same program to evaluate P(
z
)
=
5
z
4
+ 2
z
3
,
where
z
is some complex number.
Load the stack with
z
= 7 + 0
i
and see if you get the same answer as
before. (Answer: 12,691.0000 + 0.0000
i
.)
Now run the program for
z =
1 +
i
. (Answer -24.0000 + 4.0000
i
.)
Summary of Contents for HP-15C
Page 1: ...HP 15C Owner s Handbook HP Part Number 00015 90001 Edition 2 4 Sep 2011 ...
Page 17: ...Part l HP 15C Fundamentals ...
Page 64: ......
Page 65: ...Part ll HP 15C Programming ...
Page 118: ...118 ...
