168 Section 12: Calculating with Matrices
Writing down the elements of
C
,
P
1
10
11
10
11
11
10
10
0500
.
1
10
0000
.
1
10
8000
.
3
10
0000
.
1
0000
.
1
10
0000
.
4
10
8500
.
2
0000
.
1
ZZ
C
,
where the upper half of matrix
C
is the real part of
ZZ
-1
and the lower half
is the imaginary part. Therefore, by inspection of matrix
C
,
10
11
11
11
11
10
1
10
0500
.
1
10
0000
.
1
10
8000
.
3
10
0000
.
1
0000
.
1
10
0000
.
4
10
8500
.
2
0000
.
1
i
ZZ
As expected,
0
0
0
0
1
0
0
1
1
i
-
ZZ
Solving the Complex Equation AX = B
You can solve the complex matrix equation
AX
=
B
by finding
X
=
A
-1
B
.
Do this by calculating
X
P
= (
Ã
)
-1
B
P
.
To solve the equation
AX
=
B
, where
A
,
X
, and
B
are complex matrices:
1. Store the elements of
A
and
B
in memory, in the form either of
Z
P
or
of
Z
C
.
2. Recall the descriptor of the matrix representing
B
into the display.
3. If the elements of
B
were entered in the form
B
C
, press
´p
to
transform
B
C
into
B
P
.
Summary of Contents for HP-15C
Page 1: ...HP 15C Owner s Handbook HP Part Number 00015 90001 Edition 2 4 Sep 2011 ...
Page 17: ...Part l HP 15C Fundamentals ...
Page 64: ......
Page 65: ...Part ll HP 15C Programming ...
Page 118: ...118 ...
