Example 4: The square characteristic
Let the input mode = 4-20 mA, and parameters
“Lo C”
and
“Hi C”
equal to -300 and 1200 respectively. The
calculations will be done for there different input currents from example 2.
a) I
in
=10 mA and I
n
= 0,375
Accordingly to expression on page 41 for linear characteristic:
0,375 × [1200 - (-300)] 337 and next, the
“Lo C”
value is added to the result , so the displayed value:
W 562 + (-300) = 262
b) I
in
= 2,5 mA and I
n
= -0,0938.
W 441.
c) I
in
= 20,5 mA and I
n
= 1,0313.
W 1247.
a) I
in
=10 mA and I
n
= 0,375
Accordingly to expression on page 41 for square characteristic: (0,375)
2
× [1200 - (-300)]
211. and
C”
value is added to the result , so the displayed value:
W 211 + (-300) = -89
b) I
in
= 2,5 mA and I
n
= -0,0938.
W 287.
c) I
in
= 20,5 mA and I
n
= 1,0313.
W 1295.
Example 5: The square root characteristic
Let the input mode = 4-20 mA, and parameters “Lo C” and “Hi C” equal to -300 and 1200 respectively.
The calculations will be done for there different input currents from example 2.
a) I
in
=10 mA and I
n
= 0,375
Accordingly to expression on page 42 for square root characteristic:
0,375 × [1200 - 300] 919.
and next, the
“Lo C”
value is added to the result , so the displayed value:
W 919 + (-300) = 619
b) I
in
= 2,5 mA and In = -0,0938 , normalized result is negative , so the displayed value is equal to
“Lo C”
parameter: W
“Lo C”
= -300.
c) I
in
= 20,5 mA and In = 1,0313.
W 1223.
42
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