6. Status Display and Parameter Setting
6
−
25
(Example 3)
Position droop
The data unit is a value equivalent to 360
°
when the actual data = 23040000.
Thus, for a +0.1
°
position droop, 6400 is output (actual data = 0.1
×
23040000/360 = 6400.
When parameter: SP255 (SP256) is 256 (magnification =1), the D/A output voltage at this
time exceeds the max. value. (DATA = 6400 > +128)
Thus, the setting value of parameter SP255 (SP256) in this case is as follows:
DATA = 6400 * {setting value} /256 < 128
From this,
{setting value} < 5.12 (=128
∗
256/6400)
The data can be confirmed by setting SP255 (SP254) to 5.
The D/A output voltage value at this time is 9.88V (= 5V + {6400
×
5/256
×
(5V/128}).
(Example 4)
Confirmation of the orientation completed signal with control output 4L
The data unit is bit correspondence data.
Refer to section 1.1 "Spindle monitor" for the meanings of bit correspondence signals of
control output 4L.
The orientation completed signal corresponds to bit4 of the control output 4L.
Thus, bit4 = 1 when the orientation completed signal is ON, and the following is output:
Actual data = 16 (= 2
4
)
When parameter: SP255 (SP256) is 256 (magnification =1), the data can be confirmed
because the D/A output voltage is smaller than the max. value (DATA = 16 < +128)
The D/A output voltage value at this time is 5.625V (= 5V + {16
×
256/256
×
(5V/128}).
Note that when a bit other than bit4 is ON, the voltage of that bit will be added to the 6.25V
above. Therefore, confirm the data with the changed voltage of 0.625V (= 5.625V
−
5V) during
measurement of the actual orientation completed signal.
(Note) When the orientation is completed, the index positioning completed signal (bit7) turns
ON simultaneously, so the actual data = 128 (2
7
) is added.
∗
D/A output voltage = 5V + { (16 + 128) x 256/256
×
(5V/128)} = 10.625V
[Reference]
When 10V is exceeded as in the above, the data will overflow. Thus, the actual
voltage V becomes (= calculated D/A voltage
−
10
n : n being the largest
positive integer when the right equation is positive.)
(Example)
When the index positioning completed signal above is added.
V = 10.625
−
10
∗
1 = 0.625 (V)
0
OFF
ON
Motor speed
Orientation
start
Orientation speed
Orientation completed
signal OFF
Orientation completed
signal
5
Orientation time
10V
D/A output voltage (V)
(speed FB)
0V
5.625V
0.625V
Time