– 17 –
tan
–1
1=[g]
”02@T
1
=
50.
”00
(cosh 1.5 +
ª(hu
1.5
+h
sinh 1.5)
2
=
s
1.5
)L=
20.08553692
tanh
–1
— =
@Ht(
5
/
7
)=
0.895879734
ln 20 =
I
20
=
2.995732274
log 50 =
l
50
=
1.698970004
e
3
=
@e
3
=
20.08553692
10
1.7
=
@¡
1.7
=
50.11872336
— + — =
6
@•+
7
@
•=
0.309523809
8
–2
– 3
4
×
5
2
=
8
™±
2
-
3
™
4
*
5
L=
–2’024.984375
(12
3
)
—
=
12
™
3
™
4
@•=
6.447419591
8
3
8
÷=
512.
¿
49 –
4
¿
81 =
@⁄
49
-
4
@$
81
=
4.
3
¿
27
@#
27
=
3.
4! =
4
@!=
24.
10
P
3
=
10
@q
3
=
720.
5
C
2
=
5
@Q
2
=
10.
500
×
25%=
500
*
25
@%
125.
120÷400=?%
120
/
400
@%
30.
500+(500
×
25%)= 500
+
25
@%
625.
400–(400
×
30%)= 400
-
30
@%
280.
1
6
1
7
1
4
●
逆三角関数の結果は、次の範囲で表示されます。
π
2
π
2
θ
= sin
–1
x
,
θ
= tan
–1
x
θ
= cos
–1
x
DEG
–90
≦
θ
≦
90
0
≦
θ
≦
180
RAD
– —
≦
θ
≦
—
0
≦
θ
≦
π
GRAD
–100
≦
θ
≦
100
0
≦
θ
≦
200
5
7
EL5060E̲040615
04.6.15, 6:09 PM
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