Sharp PC-1500, Applications Manual

Page 1: ...I J I I I Ithis PDF Do not sa T I ...

Page 2: ...All and more about Sharp PC 1500 at http www PC 1500 info Do not sale this PDF ...

Page 3: ...bers are not always in series There arc numbers skipped Hardware Configuration Optional equipments required to execute the program are shown right below the PROGRAM NO if any CE I50 color graphic printer cassette interface CE 151 memory module CTR cassette tape recorder Outline The brief explanation concept of the program is shown Operating Guide Shows the brief explanation of how to use and opera...

Page 4: ...nstruction manual of the PC 1500 Please make sure that you read through the instruction manual first then try to type in the programs listed in this applications manual Also make sure that you use these programs after through checks through such as the examples Sharp Ctlrporation and or its subsidiaries assume no responsibilities or obligations to any los es or damages that could arise through the...

Page 5: ...T ORIDER DIFFERENTIAL EQUATION 23 DETERMINANT 26 INVERSE MATRIX 30 MATRIX PRODUCT 33 CORRELATION COEFFICIENT LINEAR REGRESSION AND PLOT 36 EXPONENTIAL REGRESSION AND PLOT 40 MODIFIED EXPONENTIAL CURVE 43 LOGISTIC CURVE 47 MODIFIED MOVING AVERAGE 54 TEST OF MEAN VALUE DIFFERENCE AND VAREANCE RATI0 57 ONE WAY LAYOUT 62 TWO WAY LAYOUT WITH NO REPLICATIONS 65 THREE WAY LAYOUT WITH NO REPLICATIONS 68 X...

Page 6: ...CONVERSION 116 LENGTH AND AREA UNIT CONVERSION 120 CALCULATION OF HOUSEHOLD ACCOUNTS 124 INVERTORY CONTROL 134 MANAGEMENT OF STUDENTS ACHIEVMENTS HI POCKET COMPUTER SCHEDULE PLANNER I51 PURCHASE LEDGER GENERATION 160 BILLING LEDGER AND LIST 165 BIORHYTHM 170 BOAT RACE I74 LABYRINT H ESCAPE I78 DOUBLE ROT ATION 183 MOLE BANGING I86 SPACE EVADER GAME 189 TYPING EXERCISES I92 STOP WATCH TIMER AND ALA...

Page 7: ...TION COEFFICIENT LINEAR REGRESSION AND PLOT Refer to pa e 37 EXPONE NTIAL REGRESSION AND PLOT Refer to page 41 1 Do not sale this PDF COLOR PRINTOUTS LOGISTIC CURVE Refer to P IJ C f9 x 1 X R CONTROL CHART Reier to palfc 75 l X CONTROL CHART CON TROL CHART LCL CL UCL ...

Page 8: ...0 2 4 6 B COLOR PRINTOUTS GRAPH GENERATION II BAR OR BROKEN LINE GRAPH Reier 10 page I SALES CHART z 0 fTI z z ri n r fTI SALES CHARl GRAPH GENERATION I BAND OR CIRCLE GRAPH IRc cr to oa 11e I00 1 0 TO 10 9 09 I I TO 20 27 27 21 TO 30 20 15 31 TO 40 15 9 41 TO 50 I J 36 51 TO 60 9 09 6 1 TO 70 6 93 Do not sale this PDF 2 ...

Page 9: ... 40 10 M ASTER TABLE l DESK 500 250 2 BED 100 200 3 CHA JR 500 350 TABLE 1 DESK 490 250 2 BJCYCLE 60 200 3 CHA IR 500 350 4 TABLE 150 100 PRESENT STOCK LIS T 2 BJCYCLE 60 200 Do not sale this PDF COLOR PRINTOUTS MANAGEMENT OF STUDENTS ACHIEVEMENTS 3 Refer to pa11e 143 AVG OF ALL 5 U AR ANCE 8 HISTOGRAM 0 6 I l 15 2 I 25 b I 3 J 36 p J 4 l 4 ti 51 I 56 l 5 l t 66 l J I 7 6 1 l 3 81 85 91 1 96 J__ I...

Page 10: ...Refer to paJle lil I DATE 1981 NAME SHARP BJRTH 1952 J 28 PHYSJ CAL EMO TJONAL lNTELLEC TUAL 0 JS 20 25 31 Do not sale this PDF COLOR PRINTOUTS COMPUTER DESIGNED FLOWER Refer LO paJle 198 COMPUTER GRAPHICS Refer to page 200 1 DOT PATTERN DEVELOPMENT Refer to page 207 4 ...

Page 11: ...rval Starting Point Section No Output Root value Press the I ENTER I key to find a root for the next interval Example I x3 2x2 x 2 O Root 1 1 2 Calculation is made with the starting point being 0 the minute value being Io and the interval being 0 5 Write a function as a subroutine after line 500 How to write a subroutine in the above example I Set the PRO mode by pressing the key 2 SOOD x 2 x I x ...

Page 12: ...AN PS A I Key Operation Procedure I Step No Input Display Remarks 1 IDE CD STARTING POINT 2 0 ENTER I MlNUTE 3 0 0001 ENTER I INTERVAL 4 0 5 l ENTEA I ANS 2 Repeal e I to f1 11d 5 IEKTER ANS I nexl root 6 ENTEA I ANS 1 ENT I ANS I IENTER I ANS 1 NTER j ANS I IENT I ANS 1 ENTER I ANS 2 Do not sale this PDF 6 ...

Page 13: ...UA L W D f x h 40 G U F U Z 0 E 50 IF Z 0GOTO 70 J 60 G G W C G GO IO F 80 G J 70 C G Z l H 80 GOSUB 300 90 F F W C F I 100 G OSUB 300 J I l0 GOTO 50 J20 ENO K 300 X C GOSUB 500 L 3J0 Y B X A C M 320 60SUB 500 330 0 C C O A Y 8 N Y 0 340 l F ABS 0 C JE SGOTO 300 p 350 BEEP 3 PRINT 0 ANS o C R 360 RETt JRN 500 B X 2 X I s X 2 T 5 J0 RETURN v v Starting Point input value STATUS J w Interval input 30...

Page 14: ...ensions Pollllr to Rectangular Rectangular to Polar o three dimensions Polar to Rectangular Example 1 Two dimensions 2 Three dimensions I a Rectangular Polar a Rectangular X 1 Y 3 Polar n 2 X I 11 3 741657387 120 b Polar Rectangular R 2 X 1 0 1 20 y I 732 ContentsI Formulas I Two dimensions a Rectangular Polar When x y 0 then r 0 therefore 8 can t be defined Y 2 0 53 30077479 Z 3 116 5650512 b Pol...

Page 15: ... O then P 90 x x Whenx O and y 0 then 0 Tan 1 y x I 80 Whenx O and y O then O Tan 1 y x 180 b Polar Rectangular Ix r Co s 0 Cos I y r Co s O S in I z r S in 0 oE I CD two dimensional Rec to Polar IDEF I m two dimensional Polar to Rec lo I CD three dimensional Rec to Polar iEFj m three dimensional Polar to Rec Key Operation Procedure First set to the degree mode jstep No Input Display Remarks 1 l I...

Page 16: ... T I TLE COORDINATES AND POLAR COORDINATES PS A 2 Stop No Input Display Remarks 4 3 IENTER I R 3 741657387 5 IENTER I THETA 53 30077479 6 IENTER I PHI 116 5650512 1 foEFj 0 R 2 3 741657387 IENTER I THETA 3 53 30077479 IENTER I PHI 4 116 5650512 IENTER I X 1 00000000I 5 IENT I Y 2 6 IENTER I z 3 Do not sale this PDF 10 ...

Page 17: ... PRINT THET A 605 RET URN G c 61 0 USING X R fCO S 64 ENO C Y R JCOS C H 70 9 G OSUB 600 RETURN I 7S X R JCOS C Y Rl 700 A Y 0 SGN Y SIN c RETURN J 80 USING PRINT X USING tttttf K 1111111111 111111 x L 83 USI NG PRJ NT US ING llttll STATUS 1 M 1111111111 111111 y 655 N BS ENO 90 C GOSUB 500 0 100 INPUT Z 11 2 p J J0 R f X f X Y Y Zl Zl Q I20 IF R 0GOTO 30 130 C A SN 2 R R r 140 IF X 0LET F s ATN Y...

Page 18: ...e function value r 2 i Output Fourier coefficie111 output The outputs of Fourier coefficient ui up Io N 2 and bi up to N 2 1 of function f t are possible Note that the No of divisions N for input I mus be even number and 176 maxin1urt1 Example I Function values for n I to 10 whc 1 one period 0 211 of a composite wave forms f t Cos 2t 3 Sin t 7 Sin 31 f l 8 729771 f 2 2 070344 f 3 2 070341 f 4 8 72...

Page 19: ...0000328 B 2 2 31 0925336E 06 B 3 6 999998884 B l 2 2J9255066E 06 Key Operation Procedure top No Input Display Remarks No of divisions within 1 1m N a period 2 10 ENT Y J 3 8 729771 IENTER I y 2 1 4 2 070344 IENTERI y 3 5 2 070341 I WTEA I y 4 6 8 729764 IENTER I y 5 7 I IEHTEA j y 6 8 8 11173 IENTER I y 7 1 9 0 45231 j ENTEA I y 8 10 0 45231 j ENTEA I y 9 11 8 1 I1737 IENTER I Y IO 12 I IENTER I P...

Page 20: ... CLS 90 NEXT l G 95 RAOIAN H 00 A 0 I IJ0 FQR J 0TO N l 120 A A Y J NEXT J J K 30 A A N LPRJNT A 0 A L J 40 FOR J JTO N 2 M J 50 P 21RIJ N A 0 N No of divisions 160 FOR J JTO N i 0 A A YC J l COS 0 PIJ p 21 1 N 180 NEXT J 90 A Al2 N a 200 AS A STR I R II s 2J0 LPRJ NT A Q 220 NEXT I T 230 FQR J ITO N 2 u I 240 P 21RIJ N 8 0 v 250 FOR J I TO N w 260 8 8 Y J I SIN x P J 2 0 NEXT J y 280 8 8 2 N z 29...

Page 21: ...y in the x coordinte to interpolate Output 4 Interpolated value X keyed in x coordinate to interpolate Z P Interpolated value y axis The above 3 and 4 can be executed repeatedly Example Number of coordinates 4 Coordinates 5 3 8 9 I 2 4 6 1 Values to be interpolated 7 Contents Formulas I To make interpolation using Lagrange s interpolation polynomial determine the value required for interpolation A...

Page 22: ...on Procedure I Step No Input Display Remarks Number of coordinates I I m N MAX 61 2 4 IfHTUI I x I 3 5 ENTER I y I 4 3 IENTER I x 2 5 8 IEHTEA J y 2 6 9 I HT R I x 3 7 12 I TE I y 3 a 4 IENTER I x 4 9 6 I NT R I y 4 li ill Execution is completed 10 I z by pressing only I E T Key opcracion returns 11 7 IEHT A I z back to Step 10 12 ENTER Do not sale this PDF 16 ...

Page 23: ...l J I v 43 CL S J v 4S PR INT A v 46 INPU T y J K 4 CLS L 50 NEXT I M SS CLS INPUT 2 Z GOTO 60 N Number of data 56 END 0 60 P 0 f 0R 1 0TQ N Value to be deter 70 BCKY I p mined by interpolao t 80 FOR J 0 TO N ing Z 90 I F J KTHEN 110 J00 8 K B K Z X Q J l X K X J R 110 NEXT J s 120 P P B K Y K T 30 NEXT K u J40 LPRJNT x z JS0 LPR JNT P P v J60 GOTO 55 w x STATUS I y 362 z Interpolated value A Inpu...

Page 24: ...n A JDEFI II for the root of a cubic equation B 2 Coefficients input For A Coefficients a band c inputs For B Coefficients a b c and d inputs Output Root value REAL X and X2 will be printed out for 2 real roots DOUBLE and X1 will be printed out for a double root REAL IMAGINARY real part and imaginary part will be printed out for an imaginary root I Example I 1 Root of a quadratic equation 4X1 X I ...

Page 25: ...of y x 3 y 3 PY q 0 b a p c 3 9 let Y u v then the following is obtained MS T V 3 U U t t 3 P U T 4 0 Let u3 p 3 q then uv p ti 13 q u v Pl This shows that u3 and v 3 are the roots of a quadratic equation of t2 qt p3 0 That is to say q 4p q f 1 4p 2 From this the roots a Jl and Y of y3 3 py q 0 become as follows The above are to be divided into the real and imaginary parts 2 I When q2 4p3 0 u3 and...

Page 26: ...ent real roots PROGRAM NO PS A 6 3 When p1 4p3 O and p 0 u 3 v 3 i is obtained Therefore from U V V i 2u f3 Y u This is the case of a double root and a another root 4 Ifq2 4p3 Oand p 0 q 0 is obtained Therefore since u v 0 the result is a f3 Y 0 This is a triple root Adding to 3 and Y finds solutions to the equation Be noted that when 2 or 3 different roots arc very close to each other they may be...

Page 27: ...No Input Display Remarks 1 1 m A _ 2 4 I HTER I ll 3 I I l TE I C 4 I I I Printout Key Operation Procedure I Step No Input Display Remark s 1 fil l m A 2 5 1 n I B 3 4 I r n I C 4 I I HTEA I Printout Key Operation Procedure I Step No Input Display Remarks 1 IDiF I ITJ A 2 I IEJ TER I B 3 I r 1 C 4 2 IOOlA I 0 5 2 It HTlA I Printout Do not sale this PDF 21 ...

Page 28: ... END 450 U R lNT M AGIN 90 LPR fNT DOUBLE ARY C ABS A I B Bl 100 END 460 END J I J0 LPRINT REAL0 470 BEEP 3 IF 10 K B JD 8 A85 D 120 LPRJNT REAL LPRINT TRIPLE L 8 JO ROOT F ENO M 130 ENO 480 A A8S S tl 210 8 JNPUT A IA l 3J l SGN E N O 8 0 F C 490 LPRINT REAL R G O H OOT 2 A F 0 220 F F O G G O H 495 LPR INT DOUBLE p H 0 ROOT A F 240 I 13 500 EN D a 250 0 G 3 F F 260 E H F G 2 FtFt R F s 2 0 C 4t0...

Page 29: ... n l h and x0 nh Example I Equation y x y is solvecl uncler the initial condition of x0 0 provided Yo I0 However assuming h 0 0 I T 0 03 y is obtained with x 0 03 0 06 and so on Contents Formulas Assume that the equation is y f x y with its initial condition of x0 y0 With the x value taken in h increments sequentially determine Yn of they value in Xn xo nh n I 2 The formulas for detem1ining Xn 1 a...

Page 30: ...3 y 9 99550101 3 X 0 06 Y 9 982015191 X 0 09 Y 9 859581904 X 0 12 Y 9 928258582 X 0 5 Y 9 888130449 X 0 18 Y 9 839305144 X 0 2 1 Y 9 78191 3245 I Key Operation Procedure Step No Input Display Ramarks 1 loEF I I XO 2 0 I ENTER I YO 3 10 IEHTER I H 4 0 01 I EHT I T 5 0 03 IEHTE I 0 03 9 995501013 6 I ENTER I 0 06 9 982016191 Do not sale this PDF 24 ...

Page 31: ...H 2 GOSUB 500 H h 70 K H F R B K Q I Y Y R J 80 Q Q 3 R B K 90 GOSUB 500 K v J00 K H F P A K Q L Y Y R IJ 0 Q 0 3 R A K M 120 X X H 2 GOSUB N 500 0 130 K H F R K 2 0 6 Y Y R p 140 Q Q 3 R K 2 0 Qn 150 l F X ZLET S X Yl Y GOTO 30 R 160 IF X ZGOTO 200 s Xn 1 170 Y2 Z S Y Yl Interval of H Yl T 1s0 BEEP 3 LPR1NT solutions u x 2 u 90 LPRINT Y Y2 GOTO 210 v 200 BEEP 3 LPR1NT w X X 20S LPR1NT V y x Xn 2J...

Page 32: ...ts of the matrix Data verification and correction ol data Output of input data and calculati On results Execution of the determinant Output of calculation results only The l EF I 0 prints out the input data The order is possible up to 12 I Example r4 7 I 8 5 I 2 4 3276 3 12 5 6 L I 4 7 2 _ Contents Formulas This program converts the matrix into a triangular matrix by using the sweeping 0ut method ...

Page 33: ... Procedure Oat a input Step No Input Display Remarks 1 OEF I IT N No of the order input 2 4 l vrrE I A I 3 4 I ENTER I A l 2 4 7 I ENTER I A J 3 5 I j vrrER I A J 4 6 8 EHTEA I A 2 J 7 5 ENrER I A 2 2 8 J ENTER I A 2 3 9 2 EHTEA I A 2 4 10 4 ENTER I A 3 1 11 3 ENTER I A 3 2 12 2 I ENTER I A 3 3 Incorrect data input 13 5 I ENTER I A 3 4 14 6 I ENTER I A 4 1 15 I I ENTER I A 4 2 16 4 I ENTER I A 4 3...

Page 34: ...Remarki 19 loul m A l l 4 20 IENTER I A l 2 7 21 IENTER I A l 3 1 22 IEMTDl l A l 4 8 23 1 1 A 2 1 s 24 IE rTER I A 2 2 I 25 IOrr R I A 2 3 2 26 IDtTER I A 2 4 4 27 IEXTOi I A 3 1 3 28 1 1 A 3 2 2 29 12 IEJITDI I A 3 3 s Correct data input 30 1 A 3 4 n 6 31 A 4 I I 32 I A 4 2 s 4 33 IEXTDI A 4 3 7 34 Iam R A 4 4 2 35 Ifl TER I 36 1 1 m Outputof input d1t11nd result Do not sale this PDF 28 ...

Page 35: ...HEXT I F 6S PR NT A RETURN G 0 INPUT A J J 900 LPRINT ERROR CLS ENO H 80 NEXT J 120 NEXT I END I v 130 8 FOR 1 0TO J v N STATUS I 584 140 FOR J 0TO N K 1se A A STR l t 1 STRS L J l M v 160 CLS PR INT Q A l J N Number ofthe order 165 CURSOR LS 1 0 J NPUT E A l J 0 E p v 1se NEXT J 200 NEXT J EN O a J 2 J0 C GOSUB 500 21s o FOR M NTO R STEP I s 220 P ACM M 225 IF P 0 T MEN 900 T 2Je F OR 1 0TO 1 1 I...

Page 36: ...ion of n order matrix elements Execution Inverse matrix determination Output Output of the entered matrix elements The output appears after a beep tone The order is possible up to I I Example t I 2 I 3 I I Contents Formulas 4 2 0 5 Assume that a matrix is A iaij I i I a j ai l i l n P lmm 1 m l n O m j m P j 1 n ft i a i a JJI a i i 1 ri i Oi i l ii _ 1 i l 11 After computation aij turns out to be...

Page 37: ...l 1 Oat ir put 3 I It n I A l 2 4 2 l l HTOl I A l 3 5 2 l mnu l A 2 1 Wrongdata 6 1 TU I A 2 2 7 3 ILNTiiil A 2 3 8 2 IE Nu iil A 3 I I 9 I ICHT I A 3 2 10 1 I HJ I A 3 3 11 4 IElnCR I I ou ITJ A i 1 I 2 I EAI A l 2 2 3 IEHTE I A i 3 2 4 0 ttHT R I A 2 l l Correct data input 5 If NTEA I A 2 2 3 6 IVITE I A 2 3 2 7 IunER I A 3 I I 8 I A 3 2 I 9 Ivcru j A 3 3 4 10 ENTER I I 11 oul Printout Do not s...

Page 38: ...8 550 EN O H 80 NEXT J 500 FOR 1 0TO N I 120 NEXT I ENO Sl0 FOR J 0T0 N 130 B FOR 1 0TO 520 A A STR J I N l I STR 140 FOR J 0TO N J K 150 AS A STR 530 LPRINT A A J L 41 STR J v CJ l 0 540 NEXT J NEXT I M 160 CLS PRINT 0 RETURN N No of the order A J J 550 BEEP I FOR 1 0 165 CURSOR 5 TO N 0 170 INPUT E A J Jl 560 FOR J 0TO N E 5 0 A C STR p 180 N XT J 1 1 STR 0 v 200 NEXT l END CJ l t e 2J0 C GOSU8 ...

Page 39: ...the elements of matrix A 2 Input of No of columns n in for matrix B Key in the elements of matrix B The limits of Q m and n are l m n S 170 Output The outputs ofelements of product matrix C Example I m I type matrix A l n type matrix B Product mn type matrix C r l 4 0 1 I 3 3 7 6 9 2 s I 5 1 3 L Contents I Formulas The following calculation is carried out Cii L tli4 bt _ i 2 m J I 2 n r b b1r b1r1...

Page 40: ... L No f rows input for m2 type matrix A No of columns input for 2 4 ID mi I M 4 L m2 type matrix A Elements input for m3trix 3 3 I HTIR J a l l A 4 4 1 1 a t 2 5 0 IENTER I a l 3 6 I IENTER I a 2 J 7 3 I a 2 2 15 3 HTER I No of columns input for L 3 N l n type matrix B Elements input for matrix 16 2 IENTER I b l 1 B 17 1 IENTEi i b l 2 18 s IENT I b 2 1 19 6 I re I b 2 2 20 6 IEHTDI I b 3 l 21 I I...

Page 41: ... v 70 NEXT J NEXT j I 80 CLS PRINT L J v L J CURSOR 8 K v 90 INPUT 11 N 1 N N N J Columns for matrix 100 0JM C M N L A Rows for matrix B l J0 FOR 1 0TO L Ruwsof matrix A 120 FOR J 0 TO N M 130 A b STR Columns of matrix l l STRS N B CJ 40 CLS PRINT A 0 50 JNPUT B p 160 FOR K 0TO M I70 C K J C K J Q A K l B R J80 NEXT K NEXT J s NEXT I 190 FOR 1 0TO n T FOR J 0 TO N u 200 A c STR v l J STR J I w 2 J...

Page 42: ...nd mean value are calculated for printouts 3 The graph with X and Y centered on the X axis and Y axis is generated on which the input data and estimated values are displayed in different colors 4 The estimated value Y is determined from the value X for the printout of the X and Y values I Example I x 6 9 7 6 7 6 9 0 8 1 6 5 6 4 6 9 Y 12 JO 9 S 6 IS 14 12 Covaria nce 3 060714286 Correlation coeffic...

Page 43: ... y 10 3 5 X 4 Y 10 27644895 Key Operation Procedure Step No Input Display Remuks 1 1 1CD X _ 2 6 9 IEHTDI I Y The display returns to step I Press tho I NYE I key 3 12 j EHTEA I X in step 2 or repeat the procedure until JO sets ofdata are keyed in 18 IENll ft I Data output with the dis play ends 1he operation 19 loEF II during which the vari ance and other data arc printed 20 lou m ESTl M ATION The...

Page 44: ...R lNT MEAN 364 LPRJNT X I 365 LPR INT Y J 370 ENO 500 0 GRAPM 5 J0 A O Pl 200 520 8 Q Rl 350 530 C J P A 540 0 R J 8 550 GLCURSOR C 0 560 0RGN 570 Xl J P A YI 0 580 X2 0 ll A Y2 0 590 GQSU8 900 600 LINE X2 J0 Y2 10 X2 Y2 605 LINE X2 Y2 X2 I 0 Y2 10 6J0 LPRJNT 620 LJNE CX2 J0 Y2 23 cx2 t 2 23 630 X J 0 YJ J R 8 640 X2 0 Y2 0 J B 650 GOSU8 900 660 LlNE CX2 J0 Y2 J0 CX2 Y2 665 LI NE C X2 Y2 X2 J0 Y2 ...

Page 45: ... Par I dot y data table c J C D J DS E J E X1 Line r lraw subroutine Start X coordinate F FS Y1 Line draw subroutine Start Y coordinate G GS X2 Line draw subroutine End Xcoordinate H HS Y2 Line draw subroutin End Y coordinate t x 1 J y J K Sxx 1 Xi2 nX2 KS L Sxy 1 Xi Yi nXY L S M Syy l Yi nY2 MS N Number Data n NS 0 X MAX 0 p X MIN PS Q Y MAX 0 R Y MJN RS s Regression ooefficjcnt i S T Rcgrc5 ion ...

Page 46: ...stimations the estimated y should be less than the maximum value of the input data Y 1 2 3 1 7 4 n 4 y 7 01 I 1 72 44 54 936 71 Apply the above data to y ab and estimate the values when x 2 4 6 and 6 5 I Contents I Formulas Find the coefficients a and b so that the graph of y ab I is most applicable to the given number n of points x1 y 1 x2 y 2 Cxn y0 The method of least squares is normally used f...

Page 47: ...Y 495 49304 76 I _ 01 Key Operation Procedure I jstep No Input Display Remarks 1 oEFI 0 N 2 4 I EllTER I X l 3 0 5 IEIITTR I Y i 4 7 01 IENTER I X 2 5 1 2 I EKTER I Y 2 6 11 72 I EJITER I X 3 7 3 1 I EllTER I Y 3 8 44 54 I ENTER I X I 9 7 4 I ENTER I Y I A B R arc printed out to 10 936 71 I ENml I complete key operation 11 IDE I 0 ESTIMATION X Display appears after the graph output 12 2 I ENTER I ...

Page 48: ...400 N No ofcoordinates XCJ 395 LINE J K J J 0 l Xi I J6 IF F Y I LET F K J Jl K K l Y J GOTO 380 p 1 Y 11 B lF G Y I LET G 400 0 X i Y l 410 IF I NTHEN q Q 120 0 0 X l P P Y 0 R J Y J30 0 0 X l XCJ 420 CLS INPUT ES R R Y Y S S X TIMATION x X s XiY l Y J GOTO 440 140 N XT I 430 N l GOTO 470 T Sxx l 50 X O N Y P N 4 40 J X l L Y l u Sxy 160 T 0 N X X A B X l K Y l 170 U S N X Y M v Syy l80 V R Nt Y ...

Page 49: ...nput No ofdata Output jCoefficient a b k value Estimate x y x Y Estimate x No of data is possible up to 36 Cassette tape File name MEC OATA K oul TI k is unknown Input INo of data Output Coefficient a b k yi Estimate x y Estimate x No o f d ata is unlim ited The cassette tape file na_ mc is MEC DATA Example I I k is known k 550 Xi I 2 12 35 60 Estimate x 5 x 1s Yi 540 2 54 0 4 542 545 547 2 k is u...

Page 50: ... x Y tx txY n I x2 I z B _ n t tY IxIY ni x Ix 2 k is unknown Datas assumed as 3n if No of datas is undividable by 3 the remainder is omitted is divided into 3 parts 0 x n n x 2n and 2n x 3n with sums of respective parts written as L Y 2 yi I y 2 u i I L Y E YI t 2 I the following is obtained I b l y I y I 1y I y l y I y b l b 1 2 I b l k I 1 y a b I I Printout I o 10 0556453 b 9 80 8 1777E 01 STI...

Page 51: ...TER I y 2 Repeated data input 13 60 I J TER I y 5 14 547 I ENTER I DATA CSAVE Y N After data print 15 Y I l TER I X Data output to cassette tape N I NTEJI I X 16 s ERI X x Input 17 15 I ENTER I x a x Input 18 I EHTEll I End Key Operation Procedure I k is unknown StepNo Input Display Remarks 1 Io e JIT DATA CLOAD Y N _ After data input from 2 y IENTEll j DATACSAVE Y N _ cassette tape and data print...

Page 52: ... 1 C H i xi v 701 CL S t lt X 280 570 8EEP 3 LPRINT STRS 300 I F N GOTO o A I 00 380 LPRINT ib S 80 PRI HT AS 3 0 PR JNT tl MEC OA 590 LPRJNT k c J 90 INPUl X I TA K O C 600 8E P 5 INPUT GOTO I l 0 320 PR JNT U MEC OA DAT CSAV Y K J00 CLS O J J TA K X Y N il L y i SO TO 180 6J0 JF i tS Y CA ll0 CLS QS Y 330 GOTO 700 Ntt IGOTO M STRs l l 400 6 CLE R 600 620 IF AS N GOTO L IAJT 0 CLS N n 120 PR I NT...

Page 53: ... k X1 Xn Y 1 Yn Output jCoefficient a Coefficient m Used for coefficient calculation when k is unknown Input jn No of data Y 1 Yn Output lCoefficient a Coefficient m Coefficient k The effective number of data is up to the multiple of 3 Graph data and plot outputs of estimate value Input Estimate value X The number of estimate value inputs is up t o the number of data designated by the l I 0 and l ...

Page 54: ...Contents I Formulas I k is known y 1 me 2n Natural logarithm k 1 me y k fn l Pnm ax y Putting Y 2n I A 2n m B a the following is obtained y From the least square method the results are I r IY l xl x Y A n2 x Ix I B nl xY IxIY nl x Ir a B 2 k is unknown The reciprocal of both members in a curve formula is taken to write the following 1 1 m c y k k with 1 1 m Y K mT A T B c y Y K AB is obtained This...

Page 55: ... a t nB k 1 K m kA Printout The real printout is colored Refer to page I A 5 026266613E 01 M 48 10443978 y ESTIMATE X 5 Y 39 8192162 X 12 Y 174 8033605 Do not sale this PDF x A 2 507446178E 01 M 50 49168896 K 2115 6729 l ESTlMATE X 10 Y 413 71 32289 X 15 Y 973 0535461 K 18 Y 1361 923995 X 19 Y 1478 76567 1 49 x PROGRAM NO PS B 4 3 ...

Page 56: ...ER I cassette tape the results 2 are printed out tocomplete processing N IEHTER I N To 3 3 3 IENTER I K 4 195 IENTER I X I 5 2 IENTER I y 1 6 I I IENTER I x 2 7 6 IENTER I y 2 8 54 IENTER I x 3 9 IO IENTER I y 3 11 0 ISO IENTER I DATA CSAVE Y N After data output to the y IENTER I cassette tape the results are printed out to com 11 plcte processing The results are printed out N IENTER I to complete...

Page 57: ...l I y 2 5 so IENTER I y 3 Repeated input 19 983 IENTER I y 17 20 1143 IENTER j Y l8 21 1256 IENTER I DATA CSAVE Y N After data input from the y IENTER I cassette tape the results arc printed out to com 22 plete processing The results are printed out N I ENT I to complete processing Key Operation Procedure I Graph output Estimate plot and Estimate value printout Step No Input Display Rtrnll k 1 oE ...

Page 58: ...30 FOR l C l A TO C A l 340 AS YC STRS J t 1 PRINT A 350 INPUT YC l XC I J CLS 360 B C 1 8 C I l Y J 370 NEXT J NEXT C l I 0 3 A 372 Yl YC0 Y2 YC0 373 FQR l ITO D l 3 4 IF Y I Y lLET YI Y I 375 IF Y l Y2LET Y2 Y I 376 NEXT I 380 INPUT DATA CS AVE Y Nl A 390 IF CAS Y l A S N IGOTO 380 400 lF AS N GOTO 425 410 PRJNT NO A PRINT WX Y 1 B GOTO 4 25 420 INPUT O A OlM X 0 1 YC0 1 8 2 INPUT WX Y I BC GOTO...

Page 59: ... I X min on the graph 690 1 0 G LY B 2 8 0 2 1Y 700 IF l O JNPUT STIMATE X XC H ExY B 1 E2 Y GOTO 730 I y 8 2 2 3y 7J 0 ENO J y 01 J 730 Y J C J A K Yl Min of Yn EXP B fX l S XCJ N R Y L Graph coefficient v Y2 Max of Yn I L J l I M Range graph value 40 LJNE CS 2 R 2 5 2 R 2 0 3 N Graph coefficient X 8 GOiO 700 0 y 800 O GLCURSOR 0 0 GLCURSOR p 10 300 W Q 8J0 TEXT COLOR 0 LPR INT EST R J MA TE J 82...

Page 60: ... if any based on a cycle Operating Guide I lour 0 Number input of averaging items n of the modified moving average With the input of data the printouts are made for input values and mean values I Example I l Find the modified moving average of 4 items Data 56 79 O 97 20 23 99 68 34 93 31 I Contents I Formulas Processing varies wilh the number of averaging items n being an odd number or even number...

Page 61: ... U 53 5 X 23 M U 42 X 99 M U 47 375 X 68 M U 56 125 X 34 M U 54 25 X 93 M U 64 75 X 31 M U 65 Key Operation Procedure I Step No Input Ditplay Remark 1 DUI 0 N 2 4 IDITT I x Printoutsofdata 3 56 IDITTO x 4 79 IU TER x I 5 0 IENTER X 6 97 jEJ TEJO X 7 20 IENTER I x Printouts of mean value 8 23 IENTER I x 13 31 jEN lt J X 14 I M TER I Do not sale this PDF l 55 ...

Page 62: ...INPUT X O G GOTO 90 H BS ENO 90 E E O LPRINT I X 0 J 95 LPRINT 11 M V K E S D X C tA L J00 E E X C X C M I I I0 NEXT c N J20 GOTO 70 0 J30 FOR C 0TO A 2 p 10 GOSUB 500 J50 NEXT c a 160 8 A l INPUT x R X B s 170 E E X B LPRJ NT X T X B u 180 LPRJNT M U E tA v 190 FOR C 0TO B w 200 INPUT 1 X 11 0 x GOTO 210 205 ENO y 2J0 E X C D X C z O 220 LPR NT X X n 1 Data Table o 225 LPR JNT M U E 1A NEXT c 230...

Page 63: ...for population I No of data for population 2 Mean value of population I Mean value of population 2 Standard deviation of population I Standard deviation of population 2 Output Test value T Freedom degree Jo I IT Used for test of mean value difference processed data Input j Data of population I l Data of population 2 Output Mean value of population I Standard deviation of population 1 Mean value of...

Page 64: ...can be conducted n 6 x 2 2 11 1 7888854382 E 1 O Standard deviulion Test ofvariance ratio 1 375 1 407 1 068 I 752 I 201 I 1 042 I 223 l 633 I 773 0 779 J 033 I 217 I 615 0 673 1 252 n IO 11 3 261141757 E 1 2 0 984 1 693 0 840 n2 8 12 3 564527359 E I F testing is performed on the basis of this data Contents Formulas Test of mean value difference When 2 normal populations are equal in variance and t...

Page 65: ...878 IENTER STD DEV 2 7 0 1 788854382 IIENTEfll Test of mean value dif 8 loul CD X _ ference lnprocc d da1a Sequcnlial inputs of 9 2 J I NT I X _ population I data 10 1 6 IEMftll I X _ Repeated data input 17 2 2 E n I X Mean value and standard 18 IEHTP I X _ deviation printouts of populaiion I 19 2 3 Ie n I X 20 2 5 EHTDI I X 21 2 0 x _ 22 2 1 ENTIR X 23 2 2 Tl X 24 2 1 EHftll X 25 IENTER J 26 loul...

Page 66: ...39 IEJ TER I X deviation printouts of population I 40 I 033 IENTER I x 4i1 1 217 I ENT I X 4l7 0 840 IE NTEl I X 4l8 IENTER I Printout I Test of mean value dilference Test of mean value difference inprocessed dataI processed data MEAN 2 0 5 T l 0 6244005 STD DEV PH 12 2 3 54698 BE 0 1 MEAN 2 2 STD DEV 1 88854382E 0 1 T l 0 6244005 T ast ol variance ratio PH 12 processed datal Test of variance rati...

Page 67: ...60 B GOSUB 500 V I N l H 70 M N R 5 Y X I GOSUB 500 580 LF l RETURN 80 L M N J 90 T Y X M N K L 2 L i R S L M N 100 LPR NT T i T STATUS I LPR NT PHJ 611 M i J o of data for L 2 population 1 ll0 ENO No of data for 120 X INPUT N l N M N2 H population 2 I30 INPUT STO OEU J R 11 STO O 0 EU 2 j s p 140 R R R S S S GOTO 180 a 150 Z 605UB 500 Standard deviation 160 M N R S GOSU8 R 500 of population 1 l 0...

Page 68: ...pears key in the number of replications 3 Data input i l 2 a j 1 2 n When X i j appears key in the data Output Results of analysis of variance Outputs ofsquare sums freedom degree unbiased variance and unbiased variance ratio in between or inside classes I Example I Factor Al A2 I 255 25 S 2 265 24 S 3 27 0 235 Contents I Formulas No of levels a No of replications n A3 A4 27 5 28 0 25 S 29 5 26 5 ...

Page 69: ...667 Se 6 333333 St 32 5 OFo 3 OFe a OFt 11 Vo 8 722222333 Ve 0 791666625 Fo I I 01 754458 Key Operation Procedure I StepNo Input Oispl y Remarks 1 loul D a No of fac1ors 2 4 IENT I n No of replications 3 3 EHTEJl I x l t Data 4 2S S ENTER I x l 2 Repeal for data inputs 14 29 S ENT I x 4 3 15 28 S ENT I Printout Do not sale this PDF 63 ...

Page 70: ...O Z Z Ot0 I 100 l F L N JLET L L l 5 J 210 S S E E K 220 R R E L 230 IF l A ILET J l J GOTO 70 M 240 R R R CA N N No of replications 250 S S N 430 S S R LPRINT 0 e t Sa S p 5l0 Z Z R Q 520 P Z S LPRINT Se P LPRINT R X1 an St Z s Exi2 n Sa Va 530 F A J LPRI NT OFa F T 540 S S F u 690 0 A N l v LPRJNT 11 0Fe 11 w 0 00 P P O x 1 0 0 A N J LPRJNT y DFt O E 1 s 20 LPRINT 1 Ua 11 S z X IJ t 800 LPRJNT 1...

Page 71: ... factor A number of A levels with a Enter the dimensions of factor B number of B levels with b 3 Data input i I a j 1 b Enter the data with x ij Output Variations freedom degrees unbiased variances and unbiased variance ratios Example I Bl 82 83 B4 Al 15 1 1 29 3 A2 11 9 3 7 A3 7 1 7 19 A4 9 41 21 48 Contents Formulas Number of levels of each factor a b Data xii i l a j l b No of data ab I X x lab...

Page 72: ...e 849 5625 St 5233 9375 OFa 3 DFb 3 DFe 9 DFt 15 Ua 1444 395833 Ub 350 3958333 Ue 94 39583333 Fa 15 3014787 Fb 3 711984109 Key Operation Procedure I Si p No Input Display Remarks 1 lout ITJ a Dimensions offactor A 2 4 Ir u I b _ Dimensions of factor B i 4 I NT R I X I 1 Data 4 IS I NIER I X l 2 Repe2ted data inpur 18 21 IE TU I X 4 4 19 48 IVITU I Do not sale this PDF 66 ...

Page 73: ...NT fb F F Pa Fa Fb 77 PRINT AS 890 ENO G 90 INPUT E CLS 170 2 2 E l E H 80 0CJ O J E I J 190 P P E 200 IF J B ILET J STATUS I J J J I GOTO 75 s s K 210 S 5 P P 220 R R P L 230 IF J A ILET I GOTO 50 M 240 R R R CA Bl N 250 5 5 8 260 FOR 1 0TO B 1 0 e x 270 T T Ocl l OCJ p c i Se Ve NEXT I 300 T T A Q 430 5 5 R LPRINT Er2 i ab Sa S R 440 T T R LPRINT s l r 2 i b Sa Va Sb T T l O J a Sb Vb SJ0 2 2 R ...

Page 74: ...nsion of factor A number of A levels With b enter the dimension of factor B number of B levels With c enter the dimension of factor C number of C levels 3 Data input i I a j 1 b k 1 c These are determined by the input values in step 2 With X ij k enter the data Output Variations freedom degrees unbiased variances and unbiased variance ratios Example I Experim Thermometer Day I I I Sum entalist Cl ...

Page 75: ... x 1 1 s S T S s Sc s S xc Su e 3 a I e b I i c C 1 A B p A p p A X C p A p C P axe c f P P P c f abc 1 Printout Sa 0 84375 Sb 5 02083333 Sc 4 61458333 Sa b 0 4375 Sa c 1 03125 Sb c 2 72916667 Se 0 3125 St 14 98958333 OFa l OFb 2 DFc 3 OFa b 2 DFa c 3 OFb c 6 OFe 6 OFt 23 Do not sale this PDF 4 lVt ISi I t VT is not calculated 5 F t V t V FT and FE are not calculated Va 0 84375 Vb 2 51041 6665 Ve ...

Page 76: ...0 P P 0 STR K l 390 NEXT J NEXT I 10 O Al B C J 400 W W B X X A LPRINT OFt 1 76 A t x 8 430 S S R LPRINT Q Sa S 20 LPRINT Uo S PRINT AS 440 T T R LPRJ NT 30 LPRINT Ub T 90 INPUT E CLS Sb T 740 LPRINT IJc U 110 Z Z E E 450 U U R LPRINT 50 LPRINT Ua b 120 J Kl F J K Sc U u E 460 U U R s r 760 LPRINT UQ c 130 G l Kl G J Kl LPRINT Sa b w E u 770 LPRJNT Ubl c 140 Q K O Kl E 470 1 i W R S U x ISB H H E ...

Page 77: ...cnsionol fucior C cs 0 OS E For inpu1 ES F 9a Fa Fbc FS F 8 1 C 11 Calcula1ion of l x2 jk G Pb GS G A 1 C 1 Calculation of Ex2 k H L iij efic HS I 1 J JS K KS L LS M MS N NS 0 9a x 9o r t t 11 OS 016 1 Calcula1ion of l x2 k p Exi Sc Ye PS 0 0 O IC 1 Calcul ilion of Ex2 k R X RS s A s v SS T T O i 2 oc Sb Yb TS u U Q il ab Sc Ve us v V A B Saxll Vax b vs w i C i j 2 b S 1 Va r WS x X l F i o S1 v11...

Page 78: ...e upper control limit and lower control limit For X R control chart generation I Contents I Formulas l The mean value x for each group is calculated Total data for each group x No of data 2 Range R is calculated R Max value of each group Min value of each group 3 The total mean valuexis calculated x Grand total of mean value No of groups 4 The total range R is calculated R Grand total of range R N...

Page 79: ...0 076 1 924 8 0 373 0 136 1 864 9 0 337 0 184 1 816 10 0 308 0 223 1 777 Example I I X Rcontrol chart is generated from the next dat a sheet Grou1 Measured values No X1 Xz X3 X4 Xs I 4 6 6 6 s 2 s 5 s 9 4 3 8 10 13 9 s 4 10 8 2 3 2 5 5 3 4 4 4 6 3 3 4 4 2 7 4 8 11 10 12 8 8 3 12 12 10 9 4 4 5 3 3 10 5 3 4 8 5 11 3 12 12 13 5 12 5 5 13 10 5 13 4 I I 4 3 4 14 3 3 3 3 10 15 11 6 10 5 12 16 8 8 5 6 5 ...

Page 80: ...4 10 10 4 3 5 4 c 12 5 5 s 4 y AIJL 5 6 lVL 9 AVL l AUL 3 6 R 5 R 8 R 8 R I GROUP 3 i GROUP 8 GROUP 3 GROUP 18 l 8 I 8 l 4 l 3 2 0 2 3 2 II 2 3 3 3 3 12 3 4 3 3 4 9 4 12 4 3 4 3 5 5 5 l 0 s 4 5 3 A VL 9 A U L 9 AUL 5 7 AVL 3 R 8 R 9 R 8 R 0 GROUP 4 GROUP 0 GROUP 14 GROUP 19 y l 0 1 4 1 3 l 8 2 8 2 2 3 2 J2 3 2 3 5 3 3 3 8 4 3 4 3 1 3 4 10 5 2 5 3 5 10 5 7 AUL AVL 3 8 AVL 4 4 AUL s R 8 R 2 R R 5 xG...

Page 81: ...out is colored Refer to page I Key Operation Procedure I Step No Input 1 lou GJ y 2 N ENTER 3 s IENTER I 4 20 I ENTER I 5 5 ENTER I Do not sale this PDF X CONTROL CHART R CONTROL CHAR T LCL CL UCL __ J f I _ l t if J X R Control Chart Data Input Display Remarks DATA CLOAO Y N Ptocessing ends after data input from casctte tap NO or DATA NO OF GROUPS _ GROUP I DATA GROUP I DATA _ Repeated data input...

Page 82: ...tout epNo Input Display Remarks 1 loul m VERIFY CORR V C _ Step 6 v Iom I DATA CSAVE Y N _ After the Crification list output this display ap 2 pears c I NTIJI I GROUP Step 3 With only I u I key IEHT R I pressed proces ing ends I IENTI I NO Step 4 3 Step 2 IfNTl R I VERIFY CORR V C _ Totalization and display I IEHTD I DATA Step S 4 IfNTE I Step 3 GROUP 5 4 I I NO _ Step 4 Processing ends afler data...

Page 83: ... GROUP A GOTO 200 l90 GOTO 250 200 JF J A A N 2GOTO 180 220 1NPUT No a GOTO 240 230 GOTO 180 240 IF J B B M 2GOTO 220 245 INPUT DATA X B 1 A 1 GOTO 220 250 FOR A 0TO N 1 252 X M A 0 2 J J 0 8 22 10 8 254 FOR 8 0TO M 1 256 1F 21 X 8 A LET 21 X 8 A 25 7 IF Z2 X 8 A LET 22 X 8 AJ 258 X M A X M A X 8 A 259 NEXT B X M A X M A J M 260 X M J A Zl 22 NEXT A GOTO I 40 262 W AIT INPUT 0 ATA CSAVE C Y N A 26...

Page 84: ... LJNE 75 480 75 0 1 l 710 LINE 0 0l 0 480 0 I 720 F 450 N OX Y M 2 0 l U 75 COLOR 3 730 x1 x n 0 770 YJ F 775 COLOR 3 T J X C 780 FQR B I TO N 790 IF B NGOTO 840 000 x2 x M B Y2 Y 1 F 840 GQSUB 6000 a50 x1 x2 v1 v2 060 NEXT B 870 COLOR 2 9 0 Xl X M l 0 Yl c F 920 0A 0 1F Xl RC LET DA RU RC 75 GOTO 940 930 IF Xl RCLET DA RC OJ 75 940 TJ RC 950 FOR B I TO N 960 IF B NGOTO 101 0 970 X2 XCM J Bl Y2 Yl...

Page 85: ... coonlintte raph fuc1or FS AL R lower control limit G Group mean value GS RC Rccntrnl line H Total of each mean HS RU R upper control limit values I 1 X1 X coordinatc J J JS X2 X coordinate 2 K KS X3 X coordinate 3 L Group 1 11ax value LS X4 X coordinate 4 M No of da1a MS Yl Y coordi natc I N No of groups NS Y2 Y coordinate 2 0 OS DA X coordina1e graph factor p Total range PS DB 0 OS Tl RC A Group...

Page 86: ...lso allows you to make an equivalent conversion from the impedance of Y connection to that of connection 7 a Zc Operating Guide I Refer to the key Operation Procedure I Example I Y Conversion R 5 z 3 R 6 z 2 2 Y Conversion Ro 8 Xa 3 Rb 9 Xb 5 Contents I Formulas J Y Conversion Za z z 0 ib z z coJ Z z z c r 0 Do not sale this PDF R 9 z 5 Re 7 X e 6 E z z z 80 Zo I 76 0 13j Zb 3 I0 0 33j Zc 2 09 97j...

Page 87: ... 3l n I Z2 R _ 4 6 D T I Z2 X 5 2 HT A j Z3 R 6 9 I D T A I Z3 X 7 S DIT I ZA 8 1 761 1 284 OJ Ra X a 9 n I ZB 10 NTl A t 3 100 3 302 E 01 Rb Xb 11 lNTl lt I zc 12 EHT A I 2 091 1 972 Rc Xc 13 EHT A I Key Operation Procedure I 2 Y 6 Conversio n Step No Input Display Remerks 1 ZA R _ 2 8 IfHTE I ZA X 3 3 I 1 ZB R _ 4 9 EHT A j ZB X _ 5 5 j EHT ll J zc R 6 7 EHT A J zc X 7 6 IEHTE I Zl 8 I NTl R 14 ...

Page 88: ...Bf O C E Zb ZI J50 GOSUB 350 650 X X H COS l M Xb XI J60 F U G U 660 Y Y H SIN J N Re R 2 i 2 170 X S Y T 670 H BfF I C G Zc 180 GOSUB 350 680 X X H COS I 0 Xe X2 I90 H U J U 590 Y Y H SIN I p 200 X B O H Y C E 7J0 H D F I GOSUB 450 720 l E G 0 2J0 J U K U 730 X X Hf COS l R 220 X Dff H Y E G 740 Y Y H SIN I I 750 GOSUB 350 s 230 GOSUB 450 760 H U J U 240 L U M U 770 X H B Y l C T 250 X B F H Y C ...

Page 89: ...luded angles at individual points and distances As a result the azimuth and coordinates can be found Radiate Traverse Key in starting azimuth and coordinates Next enter the included angles and distances from starting points Example Open traverse As a results the azimuth and coordinates can be found Radiate trnverse i 10 20 30 X 245 2350m Y 221 5894m X 241 7746m X 100 y 100 X1 143 1825 Y 125 4477 C...

Page 90: ... 130 0806 X 241 7 74 6 Y 195 4664 Y 251 6998 I Key Operation Procedure St pNo Input DiSPlay Remorks 1 ID 1 0 OPEN Open traverse 2 TA Starting azimuth 3 110 2030 TX 1oo I Coordinates 4 TY 5 1oo I I 8 Included angle at each point 6 100 1010 IOITlll I L Distance 7 50 123 I NTlll I B 8 250 OS15 IINTER I L 9 71 234 IENTIN I 8 10 r I Processing is completed 1 loul m RADIATE Radiate traverse TA Starting ...

Page 91: ...11ti1141ti titiII 11111111 J i TA 11 jA K 6 LPRJN T tTX L B LPR lNT TY 11 M c N 80 lC l 90 JNPUT 8 0 0 GOTO 100 p 95 ENO 100 NPUT u L I E Q 1J0 F OEG A OEG 0 R 180 J20 lF OM S F 360 s LE T F OEG OMS T F 360 GOTO 12 0 u J30 G B E COS F H v C E Sl N F l40 F JN T OMS F w 0 00014 1 10 4 x 0 4 y 14J FO S TR 1C 11 z 142 LPRJNT FQ FOS Output message J43 JC C J50 LPR NT USJ NG IC v tl tlll tltl tl llll 11...

Page 92: ...s also based on the loan and solvency Example I A Find the loan limits on condition of monthly solvency at 150 000 12 annual interest and 8 years installment term Input Annual re payment I50 000 X I 2 Installment term 8 Annual intercst 12 B Assuming that a loan of 3 million is repaid with monthly solvency of I00 000 at 12 annual interest a calculation is made on how many months are required for re...

Page 93: ...00 000 I NSTALLMENT INSTALLMENT II 800 000 J00 000 INTEREST INT EREST 12 000 1 000 LIMIT S NO OF JNST_ a 9 41 51 35 8 4 Key Operation Procedure I Step N Input Display Remerks 1 ID FI GJ NO OF INST _ 2 slon I INSTALLMENT _ 3 I50000 12 IOITEJI I INTEREST _ 4 12 IOl TER I 5 IDE I CD LIMITS _ 6 3000000 IEHTEJI I INSTALLMENT _ 7 I00000 IEHT R I INTEREST 8 1 1DITllO I Do not sale this PLJF 87 ...

Page 94: ...PRJNT LJMJ TS I 55 LPRJNT USING J calculation Work tttUttfillttttttlllfti i tttt O K Calculation Work 60 LF 3 END L 200 B CLEAR 1 F 2 2 J0 JNPUT Lli1JTS M II 0 N 2 JS LPRINT L IM TS 0 LPRJN T USING 11111111111111 p tttt 111111 D a 220 GOSUB 400 230 K B B D C 100 R s 240 A LOG K LOG I C 100 T 250 LPR1NT NO OF u lNST USING 11 tttttt fli 11 A v 260 LF 3 ENO w 400 JNPUT INSTALL MENf B x 405 LPRIN f IN...

Page 95: ...h 90 000 at the end of a 6 month term and an interest rate of 5 2 Detennine the current annuity payable in 9 years with 90 000 at the beginning o f a 6 month term and an interest rate of 5 3 Amount of five million loan is made at an interest rate of 8 two settlements per year and repaid in 5 year installments at 6 month compound interest What is an installment at term end Interest unit I Fractions...

Page 96: ...NT JI I RATE 3 5 IVITT I TERM 4 9 1 1 NO OF INSTL _ 5 2 I I 6 1 0 1 1 m TERM END CRNT PR Term end current price displayed 7 IEHT A 1291803 8 I 1 TERM BEGNNG CRNT PR Current price due displayed 9 _ 1324098 10 1 1m OUTSTD AMT 11 5000000 IINTIR I RATE Data input 1 2 SIEHT I TERM 13 s I n I NO OF INSTL 14 2 IEHT I 15 loul m OUTSTDNG AMT AT Display ofoutstanding TR MEND amount at term end 16 IEHTIO I 6...

Page 97: ...l 00 N F NtL 70 Y J l J NJ G 80 END H 100 8 M lNT RtY I Interest rate 0 5 J J 10 WA l T PRJN T T ERM END CRNT K PR L No of installments IJ 5 CLS PRJNT M 120 S lNT RtY l M c urrent price at term l J 0 5J end l 25 WA T PRI NT T N Term ERM BEGNNG CRN 0 T PR 130 CLS PR INT s p 135 END a 140 O A INT R l Y 0 5J Outstnding amount 150 WAJ T PRINT O R at term end and UTS TDNG AMT AT beginning TERM END Curr...

Page 98: ...e estimation will be printed out Example I I Register list Product name Price With product A 15 discount A 11 1 000 rate is IO for the quantity of A 12 2 000 5 A 13 3 000 With A 15 discount is 3 000 A 14 4 000 for the quantity of 15 A 15 5 000 With these data key in them in B 11 I I00 accordance with the key opera B 12 2 200 tion Procedure for result print B 13 3 300 out B 14 4 400 B 15 5 500 2 If...

Page 99: ...S D S Printout I DETAILS REGJSTER LJST A 15 l A 1l a 5 000 l 000 5 2 A 12 25 000 2 000 2 500 3 A 13 22 500 3 0 30 A 12 4 A 14 Iii 2 000 4 000 15 5 A 15 30 000 5 000 3 000 6 B 11 2 000 1 100 A 13 B 12 Iii 3 000 2 200 10 8 B 13 30 000 3 300 30 000 9 B 14 TOTAL 4 400 9 500 10 B 15 5 500 Do not sale this PDF 93 ...

Page 100: ...R key when no change is made Press content IDmll for 26 A 14 IENTP 4000 content change 27 XTER CHANGE NO Key in register No if more 28 IENTER changes needed 29 1 1 CD Register list printout 30 l I m REGISTER No _ 31 5 IENTU I QUANTITY Key in discount rate in 32 5 ENTER I DISCOUNT RATE _ percent 33 10 Nn I REGISTER No _ 34 2 IENTER I QUANTITY 35 15 IUtTER I DISCOUNT RATE _ 36 IextEIO DISCOUNT AMOUN...

Page 101: ...f Registers ANGE NO C 51 0 W U F J00 GOTO 170 520 Y A J E W 0 60 ENO 530 USING LPRINT 170 IF C NPAUSE E As J p XCEEO REG NO 540 US ING LPRI NT Q GOTO 150 II USING llltlt 180 PRINT A C l j tltltltl tltlll A J R n 54 l LPRINT E s 190 INPUT AS C 1 542 LPRINT ju 200 CLS PR JNT A C 550 1F W 0USING T l i LPRINT USI NG 21 0 1NPUT A C 1 lltltltllllltl lllltl i l J u 215 GOTO 150 S60 USING LPRJNT Amount be...

Page 102: ... No of data class initial value class interval and number of classes 2 Setting the way of the data input Key input or cassette input Key input Data to be keyed in then to be output to the cassette tape Cassette input Data to be input from the cassette tape 3 The variance and the standard deviation are calculated for printouts 4 The histogram is printed out I Example I No of data I0 Class initial v...

Page 103: ...ge 2 UARIANCE 6 81 STD DEU 2 60959767 0 2 4 6 B Key Operation Procedure I Step No Input Display Remarks 1 lo I 0 NO OF DATA _ 2 10 I HT I INITIAL VALUE 3 0 j HTER l SECTIONAL INTERVAL 4 2 I T I NO OF SECTIONS 5 s j IENTEA I KEY IN Y N _ G y I ENT I DATA _ 7 s I lHTER I DATA With Y input kcy in dota 8 0 2 IEllTfll j DATA 16 8 Printout Do not sale this PDF 97 ...

Page 104: ...0 0 0 Y N AS 450 K I10 IF AS N GOTO 400 L 450 M N N l5 L 170 0 115 Z F 8 M J X 0 4J0 1 1 0 Q F M No of Sections 120 FOR C 0TO N 1 420 FOR C 0TO M 1 N No of Data 130 INPUT OATA 0 422 COLOR 2 Al C G OTO 150 GLCURSOR 50 0 140 GOTO 160 1 1 15 150 1F A C ZGOTO 424 LPRINT USI NG p 130 11111111 Q Q 2 IF A C FGOTO 430 CDLOR I 30 435 G INT H C N R 53 X X l 440 LJNE 0 W G s LAl i YT 55 NEXT C 1 1 G 1 1 L 0 ...

Page 105: ...as follows I 20 people age 0 to 10 2 60 people age 11 to 20 3 45 people age 2 1 to 30 4 35 people age 3 1 to 40 5 25 people age 4 1 to 50 6 20 people age 51 to 60 7 I5 people age 61 to 70 For the results refer to the Printout Contents Formulas The ratio of an item value to the total item value is displayed in percent on the graph D A J H x 100 D A J H Circle graph generation Ratio An item value To...

Page 106: ... 09 G 6 1 TO 70 6 83 Key Operation Procedure Step No Input 1 joEFI QJ 2 Oto 10 j EHTER j 3 II IO 20 IENTER I 13 51 10 60 IEHTEA I 14 61 to 70 IENTER I 15 15 IENTER I j EHTEll j 16 I HTEJR I Do not sale this PDF 1 rnnmn ljTjTjljlj Willll ll IMlj 0 TO 10 11 TO 20 21 TO 30 31 TO 40 41 TO 50 51 TO 60 6 1 TO 0 Display ITEM NAME I VALUE l ITEMNAME 2 ITEM NAME 7 VALUE 7 ITEM NAME 8 CIRCLE I BAND 2 _ 100 ...

Page 107: ...EX1 M 235 R 50 C F G 2 G GOSU8 600 X l Xl 3 250 G F 251 GLCURSOR X Y l LPRINT BS J L L NEXT J 252 GLCURSOR 1 0 150 SORGN 264 Y 0 X 0 COLOR 0 255 FOR J 0 TO 1 1 267 0 A J H l00 0 INT D 0051 100I I 00 11 J 1 ILET 0 100 N GOTO 270 269 N N O 270 GLCURSOR X YI _PRINT 8S J I 275 GLCURSOR 1 8 Y J LPRINT AS J 280 Y Y 20 282 GLCURSOR 18 Y J LPRI Nf USING M ll O USING 2B4 Y Y 20 295 NEXT J 290 TEXT LI 10 EN...

Page 108: ... 74 0 H Total item value 715 1F 0 INT Q 2 I Loop counter 2 0LINE S P J Loop counter U P 0 L GOTO 725 Pattern selection in 720 LJ NE u p s K P 0 L graph 725 NEXT 0 L Pen color code 7 40 RETURN 750 P S F OR O I TO M Loop counter 50 N Total ratio 75 5 P P 5 750 I P UGOTO 79 0 Loop counter 0 p 765 1 F 0 IN Q 2 2 0L INE P T Q P W 0 1 L R GOTO 775 7 0 LlNE P W P s Band graph X axis I T 01 L Band graph Y...

Page 109: ...ph For bar graph No I to 4 item are represented by horizontal lines in 4 different colors Differently colored horizontal doted lines represent No 5 to 8 item Example I Title Sales chart Graph selection Bar graph I Item Item name I Pen 2 Note 3 Pencil 4 Book 5 Paper Item v tluc 10 20 30 40 50 For the output refer to the Printout Type in the items on the left For the broken line graph the order of i...

Page 110: ...al printout is colored Refer to page 2 SALES CHART SALES CHART z 0 z I IT1 Key Operation Procedure I St No Input 1 1 1 0 2 SALES CHART t J 3 1 f l HniU 4 PEN I HTlft I 5 10 1 1 6 NOTE ItlfTD 7 20 I Httll 8 PENCILE tINTI 9 30 IENTE R 10 BOOK Il HTER 11 40 IH TtR I 12 PAPER 1tHT J 13 50 D T _j 14 ItlfTD I Do not sale this PDF I Display TITLE _ BAR BROCKEN LINE 2 _ ITEM I VALUE 1 ITEM 2 VALUE 2 ITEM ...

Page 111: ...S l l 1 NEXT J J GOTO 100 4B7 GLCURSOR 0 2 80 BS VALUE 50 K STRS l 490 TEXT LF s ENO PRINT BS 600 M M I L L I L Pen color No 85 INPUT A l CLS 610 IF L 4LET L 0 M 87 IF D A J LET 0 620 GLCURSOR G 0 A J LINE G 0 H N X Coordinate 90 NEXT I F 0 L B 0 00 LPRINT A 0J 530 P 0 IF M 4LET 105 0 45 0 P 2 p 110 GRAPH 700 0 0 l20 GLCURSOR 0 2 705 FOR K lTO 45 Q 50 SORGN 708 Qs0 5 R 130 lF C 2LET G 2 710 IF F O...

Page 112: ...alue to the working hours between 9 00 and 17 00 2 The loul W key is used to clear the total area to zero 3 With the work hour data 9 30 to I7 00 14 00 to l 6 00 and 17 00 to 23 I0 input 9 30 I 7 00 and 14 00 16 00 after the ID FI 0 operation then 7 30 T 500 3750 and 2 00 T 500 1000 will be displayed respectively When the proportional value after 17 00 is 1000 replace 500 with 1000 after the lo I ...

Page 113: ...ORT VAL _ soo IEMTVl I 3 oul START _ Close lnpul lhe minute as 4 9 30 I Hr END _ decimal number 5 17 00 IENTE I 7 30 T 500 6 iHT EAj 3750 1 EHTER I START _ 8 14 00 IE TE I END 9 16 00 3 TE I 2 00 T SOO 10 DtlOI I 1000 11 START _ 12 i IENTl R I 13 lat I CTJ PROPORT VAL I000 iEHTEA I 14 loal J START _ 15 17 00 I E T END _ 16 23 10 IEHrE I 6 10 T 1000 17 IEHrER I 6166 18 IE TE I START 19 20 D i TOTAL...

Page 114: ...ing 303 0 M GOSUB 500 Hours M O G 320 T T F 330 USI NG PRINT H US ING IiiII 1111 I J M T USI N G ttli111rn J o _ J K 335 USJ N G PRINT USI N G llllll Ullll L F M Elapsed Time 340 GOTO 15 N 350 B USING PRINT TOTAL 0 Starting Time US NG 111111111111 Closing Time llll j T p 360 ENO 400 C INPUT PRO 0 PORT VAL O R 420 ENO Starting Time 450 0 T 0 s 460 USING PAUSE after calculation TOTAL CLEAR T Total o...

Page 115: ...lly totals for individual items are also displayed Example I I Fixed rate method Determines the depreciation amount undcpreciated amount and total depreciation amount per term for product A with the acquisition cost of 800 000 life of6 years and remaining rate of I0 Two settlements per year 2 Fixed amount method Determines the depreciation amounts and undepreciated remainders for both product A an...

Page 116: ...mount The remaining rate is at least 5 Key Operat ion Procedure I F ixed rate method Step N Input Display Remarks 1 lo Fl D COST _ 2 800000 IEHTEA I NO OF TIMES 3 12 IENTER I REM RATE _ 4 10 I EHTElt I I DEPR 139680 5 IENT 1 1 UNDEPR x 0320 12 ENTER 5 DEPR 64832 13 IENTER I 5 lJNDEP 306489 26 IENTER 12 DEPR 16922 2 7 IEHTER 12 lJNDEP 79998 28 IENTE TOTAL DEPR 720002 29 IEHTEFt COST Processing can ...

Page 117: ...3 s ENTER I OEPR MONTH 4 6 ElfTVI I REM RATE _ 5 10 ENTER DEPR 81000 6 ENTER UNDEPR 819000 7 I ENTER COST 8 720000 I ENTER YEAR OF LIFE 9 25 E TEA DEPR MONTH 10 8 I ENTER REM RATE t J _ 11 10 I ENTER f OEPR 17280 12 I ENTER I UNDEPR 702720 Press this key for the priJlt 13 I ElfTVI I COST _ out of totals 14 ENTER I TfL COST 1620000 15 IENT R I TTL OEPR 98280 16 ENTEA j TTL UNDEPR I 521 720 17 EHTER...

Page 118: ...epreciation amount Acqusition cost S 10 s 80 E 0 G F Years of life 90 FOR I ITO B G Depreciation date J00 F INT 01 A H It0 E E F 120 A A F I v H Remaining rate 130 PRINT 1 OE J I PR i F 150 PRJNT Jj UN K J OEPR A I60 NE XT I l K J 0 PRINT TTL OEP l R E M 200 GOTO 20 N M 500 B CLEAR WA lf 0 Remaining rate N 510 INPUT COST E G OTO 520 p 0 s 1s GOTO 6 10 p S20 INPUT YEAR OF Q LIFE F R Q 530 INPUT OEP...

Page 119: ...rintout is made to the first decimal Also the allotment value of each index is printed out as an integer with round off Value to be allotted 5000 Number of indexes 3 Index I I0 5 Index 2 120 Index 3 70 For the calculation result refer to the Printout Contents Formulas Input Value to be allotted Number of indexes n Index Output Value lo be allotted Note Index total Index I Index 2 Index n Unit allo...

Page 120: ... TO BE ALLOTO 5000 INDEX TTL 200 5 UNIT ALLOTD VALUE 24 93 65586 JNDEX ALLOTM l 10 S 262 2 120 0 2993 3 0 0 J 45 Key Operation Procedure I tap No Input Display Remarks 1 louJ m VALU TO llE ALLOTO 2 5000 IENTEJI I NO OF INDEXES 3 3 I VITEJI I INDEX I 4 10 5 l Hn I INDcX 2 5 120 IENTER I INDEX 3 6 70 INTO I Do not sale this PDF 114 ...

Page 121: ... Value 90 INPUT H OH H GOTO 150 90 B E J GOTO 200 I l50 F H 0 F J 160 NEXT 0 K 200 6 A F 210 USIN6 LPRINT L VALUE TO BE A M LLOTO N 220 USING LPRINT 0 A 230 USING LPRINT p INDEX TTL Q 240 US NG LPR NT R F s 250 USING LPRJNT UNI T ALLOTO V T ALU u 260 US NG LPRINT G v 270 LF I w 290 USING LPRJNT INDEX A x LLOTM y 290 C B 1 300 FOR 0 0TO c z 310 E O l H C Index 315 INT G H Q 5 316 IF O CLET A J GQTO...

Page 122: ...nit Code to be converted Conversion Unit Code Data to be converted Outpul Converted Data Example I Volume Weight CU131CCENTIM 1000 GRAM 3750 CUBIC METER 0 001 TON 0 00375 LITER I GRAIN 57870 4 GALLON 0 2641 7 OUNCE 132 275 CUBIC INCH 61 0237 POUND 8 2672 CUBIC FEET 0 03532 USA TON 0 00413 Ex How many gallons arc equivalent Ex How many grams are equivalent to to I 0 liters one ounce How many cubic ...

Page 123: ...4 PND 5 CUBJC INCH USA TON CC I 5 U TN 6 CUBI C FEET C F 6 L 10 ONS l G L 2 64 1 G RAM 28 35002835 GL I PND J C CM 3 85 4 41193 GRAM 453 599 6 8 Key Operation Procedure Step No Input Display Remarks 1 Ion CD VOLUME WEICHT V W 2 v ENTER I Ends afler the table print 1ut 3 DEi I CD UNIT UNIT 4 3 ENTER I UNIT3 UNIT 5 4 ENTER I DATA 6 JO ENTER I UNIT UNIT 7 4 IENTER I UNIT4 U NIT 8 2 EHTEA I DATA 9 I I...

Page 124: ...ey ends pro gram Program List 10 A CLEAR DIM 290 LPRINT LI TER X 5 At 5 CLS X 2 1 15 INPUT VOLUME 295 LPRJNT L IEI GHT U W 3 N GOTO 25 300 LPRINT GALLON 20 GOTO 420 X 3 0 21541 25 IF N V N 7 W IGOTO 305 LPR1NT GL JS 4 50 l F t4 V GOTO 310 LPRJNT CUBIC 250 INCH X 4 f5l l60 GOTO 340 0237 250 LF l LFR JNT U 3 15 LPRJNT J OLUME 511 255 LPRJNT UNI T 320 LPRINT CUBI C NUMBER FEET X 5 0 2f50 LF I 03532 2...

Page 125: ...Conversion TON 380 LPRJNT GRAIN STATUS J E 2 57870 1220 F 385 LPRJNT GRN 3 G 390 LPRINT OUNCE H X 3 132 275 395 LPRINT QNC I 4 400 LPRJIH POUND J Weight 4 8 26720 K 405 LPRINT CPNO 5 L 4J0 LPR INT USA TO N 5 0 004 M 13 N 4JS LPR JNT C U T N 6 0 417 ASl0 GRAM A p s 2 6RN 418 AS 3 0NC A Q C4 PNO AS 5 U TN R 420 LF S ENO Input Value before 4 0 B LF I IJAJT s Unit Conversion 0 480 CLS LF I T Volume PR...

Page 126: ...nverted Conversion Unit Code Data to be converted Output Converted Data Example Length Area METER J SQUARE METER I MILLI MET R IOOO ARE 0 01 INCH 39 370 1 SQUARE INCH I550 00 f EET 3 2 8084 SQUAREfEET 10 7639 YARD 1 09361 ACRE 0 00025 MILE 0 00062 TUBO 0 30250 Ex How many inches arc equivalent Ex How many acres are equivalent to 10 yards to 7 ares How many yards are equivalent to 3 meters Contents...

Page 127: ...TERJ UNIT 5 UNIT 5 3 IENfER I VALUE 6 IO IENTE I UNJl UNIT Printout 7 I IENTER I UNIT I UNlr 8 s IENTER VALUE 9 3 IENTER I UNIT UNIT Printout Processing is complete 10 IENTER I with this key pressed Key Operation Procedure StepNo Input Display Remarks 1 IP D LENGTHiAREA LfA 2 A E TER I Ends after the table Ut put 3 JDEF I IT UNIT UNIT 4 2 1 NT ER UNIT2 UNIT 5 5 I ENTER I VALUE 6 7 E TER J UNIT UNI...

Page 128: ...SION PROGRAM NO 3 TITLE PS D 17 I Printout LENGTH AREA UNIT NUMBER UNIT NUMBER METER SQUARE METER M S M MILLIMETER ARE 2 M M 2 SQUARE INCH INCH 3 S I 3 FEET 4 SQUARE FEET YARD 5 S F 4 MILE 5 ACRE 5 TSUBO TUBO 5 YARD I0 ARE 7 INCH 360 0012802 ACRE 0 175 M 3 YARD 3 28083 Do not sale this PDF 122 ...

Page 129: ... 100 LPRINT M ILUM Q 6 J ETER XC I 10 23 ASC0 a S M K 00 C 2 S I u 105 LPRJNT CM M 3 5 F AS L 2 SJ TUBO 110 At 2 1NCH 240 LF S ENO M Area LPRINT ASC2 4 0 B LF J WA JT 3 XC 0 N Length 2J 39 3 01 480 CLS LF I 120 A 3 FEET PRINT UNJT LPRINT AS 3 UNIT 0 4 xc 500 CURSOR 6 JNPUT p 3 3 28084 A GOTO 510 a 130 ASC4 YARO 505 CLS ENO LPRINT A 4 510 IF A l CA 6 R 5 XC 0GOTO 480 4J l 0936 520 CURSOR 15 s J40 A...

Page 130: ...all cleared to zero on the cassette tape Type in the budget for the month The budgen amounts are printed out and saved into the cassette tape ID FI W Prints the sum total for the year lo FI ITl Clears all areas Precautions The F_ W and fI should be operated only once a month The procedure of loc I L J without DEf III after orr 0 and 0 operations causes an error Note Fifteen items are provided for ...

Page 131: ...s 15 000 and 8 I on PROGRAM NO PS D 22 Execute the procedure of I and o d in succession to obtain the resulting list on the following page For better understandings see the key Operation Procedure 2 If there is no inputs into the displayed item press only the I TE I key 3 When TAPE OUT liN OK Y N is displayed Enter Y with the tape set to the save in load to state respectively 4 When doing saving i...

Page 132: ... UTJLIT JES l 500 J 500 75 0 CLOTHJNG E P 00 500 l0 0 11 S SANJT E P 3 eee 3 000 60 0 EOUC E XP 30 eee 30 000 2 8 ENflMHJ EXP 50 550 13 SOCIAL EXP 5ee 4 500 98 0 TRANSPORTATION 130 130 2 3 COMNC TM EXP 3e0 MISC EXP 5e0 t DETO JLS r 300 12 0 12t10HTH IOAY FOOD EXP 3 888 3 808 6 8 1 0 JSJH6 EXP 15 eaa l S e ae 0 UTILITIES 1 500 1 500 5 0 ENTTMHT E CP 500 500 J 5 TAX 3 000 3 000 75 0 OTHERS 4 600 000...

Page 133: ...displayed YEAR s 1981 I DITVI I MONTH 6 11 IDITVI I DAY 7 1 1 FOOD EXP Input Nov budget ofeach item 8 50000 Il HT R I HOUSING EXP 9 20000 l HTE I UTILITIES 10 2000 NT R j CLOTHING EXP 11 1000 INTER I INS SANIT EXP 12 5000 f MTER I EDUC EXP 13 70000 I ENTTMNT EXP 14 4000 I r I SOCIAL EXP 15 5000 I TE I TRANSPORTATION 16 5600 I1 EJ T R I COMNCTN EXP 17 2500 I NT I MISC EXP 18 10000 l ur I REPAYMENT ...

Page 134: ...li 27 II I HT I DAY 28 I I I NTER FOOD EXP 29 2SOO ntfl HOUSING EXP 30 I5000 EHT R UTILITIES 31 1500 j NT R CLOTHING EXP 32 500 1 n I INS SANIT EXP 33 3000 I EDUC EXP 34 30000 I ENTIMNT EXP 35 550 ENTI SOCIAL EXP 36 4500 u TRANSPORTATIONa 37 130 I I COMNCTN EXP 38 300 IEHT R I MISC EXP 39 soo 1 n I REPAYMENT 40 4000 I NTIR I TAX 4 1 3500 1 Nn I OTliERS 42 I000 Il NTIR I SAVINGS Set the casseue for...

Page 135: ...inpul 52 tENTER I Cl OTlllNG EXP lfno inpul 53 IENTER I INS SANIT EXP l If no inptll 54 CE TE EDUC EXP If no inpu1 55 l ENTER I ENmlNT EXP If no inpul 56 EltTEll J SOCIAi EXP If no inpul 57 IENTER I TRANSPORTATIQNa 58 130 IENTER I COMNCTN EXP 1 If no inpul SAVINGS If no inpu1 Set the cas elle to save 64 IENTER I TAPE OUT OK Y N in 65 y Saving into the cassette tape is vcr 66 joEFI JU TAPE IN OK Y ...

Page 136: ...nput the Dec budget of soooo I I HOUSING EXP each item 88 I0000 IENTIA I TAPE OUT OK Y N _ Set the cassette to save in Saving into the 89 y IEHTI I casscue tape is over 90 loul CD TAPE IN OK Y N _ Set the cassette tape for loading After a moment the flle 91 Y llNTIA j HOUSEHOLD name is displayed YEAR 92 1981 I I MONTH 93 12 j t NT 11 j DAY Input the dala to ilcms re 94 I IEHTE I FOOD EXP quired 95...

Page 137: ... OK Y N _ Ser the casseue t ipc for loading After a moment the 113 Y l n I HOUSEHOLD file name is displayed TAPE OlIT OK Y N _ Set the cassette to s ive in Saving 114 v I I into the casseue tape is over 115 m TAPE IN OK Y N _ Set the casscue tape for loading After a moment the e y l D TEll l HOUSEHOLD 116 name is displayed Sum Total Prin1 for the year Do not sale this PDF 131 ...

Page 138: ...SJNG LPRJNT DETAILS 255 LPRINT BCl M ONTH B 2 0A Y 260 FOR 1 0TO 14 270 REAO AS 280 PRINT AS 290 JNPUT R GOTO 3 00 295 GOTO 340 300 8 191 8 1 1 9 R 310 B 34 8 34 R 320 USING LPRINT AS 325 USING LPRINT USING llllffllllllll I tttttt R 328 USI NG LPR INT USI NG llll fffftt ttll tt11U B l I9 US ING 1111 ff ttII 11 BCl l9 B J 3 100 330 S S R 340 CLS NEXT I 350 USING LPR INT TOTAL 351 USI N G LPRINT US ...

Page 139: ...0 USJNG LPRINT K AS 765 US ING LPRINT L US ING 11 u irn11 B U 35 M 770 NEXT I N 780 USIN6 LPR NT TOTAL 0 785 USJNG LPRJNr USING p ij UU 8 50 0 788 END 800 0ATA FOOO EXP ItembyItemAmount HOUSING EX R for that day P UTILI I JCS CLOTHING EX Total Amount for P INS SAN s r XP that day 801 DATA EDU C EX P ENTTM NT E T XP 1 SOC IAL c XP TRANSPOR u TATJOH v 802 0ATA COM NCTN w EXP MISC E XP REPAYMEH T TAX...

Page 140: ...he contents of stock file according to Com modity Table and Commodity List that arc under the minimum stock level Loading from or saving to the tape is determined at user s discretion However unless lo I CT is pressed again after the first IDEF m operation the contents of stock and data files in memory remain unchanged 5 llK I To input the warehousing and delivery of commodities Example I Stock co...

Page 141: ...he stock file 3 DEF m Prints out the commodity table and commodity lisl under the minimum stock level 4 loEl j Enter I if you want to print out this and 2 if you do not Makes a data file Commodity code warehousing quantity delivery quantity and prints out the data list Also can make up to 75 data 5 1 1 CO Clears the memory and secures the stock file and data file areas Printout I Items Jes than th...

Page 142: ...NTER CODE 7 2 IENTER COMMODITY NAME 8 BED IENTER I STOCK QTIY 9 I00 ENTER I MIN STOCK 10 200 IENTER I CODE 11 3 IENTER I COMMODITY NAME I 12 CHAIR 1ENTER I STOCK QTIY 13 500 g r R I MIN STOCK 14 350 IENTER l CODE 15 ENTER j M Sff R TAP OUT OK I r 0 2 Pressing only this key ends registration Set the tape to the cassette lo 16 I I MT l secure the tapc saving siale 1 IDE I 0 tAS l ER TAPE IN OK I N01...

Page 143: ...OK I N0 2 8 to secure the tape saving state 9 I I ENTERl 1 l oEF j CD REGISTER I RENEWAL 2 Set the master tape h the 2 2 I ENTER J t tASTt K T l E IN OK I N0 2 casscllc for the l3pc loadingstate 3 I I ENTER CODE Prints out the master table 4 4 ENTER COMMODITY NAME New data 5 TABLE ENTER J STOCKQ TTY 6 150 I ENT MIN STOCK 7 100 ENTER I CODE 8 2 ENTER I COMMODITY NAME Code lo be amended 9 BICYCLE I ...

Page 144: ...Set the tape to the ca uc to secure the tape loading state Set the master tape to the 3 I IEMTER I tASTER TAVEOUT 0K 1 N0 2 1 cassette for the tape saving state 4 I IEHTER l Key Operatio n Procedure I 5 Step lNo Input Display Remarks 1 1 u1m iAStER TA1 IN OK I N0 2 2 2 I TEA I TABLE YES N0 2 Prints out the table Prints out the commodity 3 I IENTER STOCK LIST YES I N0112 list Jes than the minimum s...

Page 145: ...A 0 I COLOR 0 510 NEXT J GOSUB 9 00 54e INPUT SfOCK L IST YES I N0 2 c 55e IF Ca JJ C 2 GOTO 540 S6e IF C 2GOTO 620 57e LPRINT PRESEN T SIOCK LISf 580 FOR 1 0TO n 590 IF ACJ J AC 0 I GOTO 6 10 6e0 GOSUB 900 610 NEXT t GOSUB 9 00 620 END 630 0 US l NG LPRJNT D ATA LIST 635 FOR 1 0f0 N 640 1NPUT CODE D 2 J GOTO 65 0 645 60TO 670 650 IF De I I GOTO 640 651 IF 0 2 l lM I GOTO 64e 653 JNPUT DELIUER Y 0...

Page 146: ...BS Commodily Name A I MI Mas1er Presenl S1ock lnpu1 Arca Mas1cr min S1ock c j cs DIZ NI ata Delivery D 11a No l a1a Warehousing D OS E Numerical Figure ES Input Area F FS G GS H HS I Loop Coun1cr IS J Loop Coun1er JS K j KS L L Number of Master M Commodilies MS Number of Da1a N Conm1odi1ics NS 0 0 p PS a OS R RS s SS T TS u us I v vs w ws x XS y YS z ZS Do not sale this PDF 110 ...

Page 147: ... number of students per class Input the mark for each subject by pressing IE E I key after the code and name are displayed In the case of amendment enter only necessary subjects Pressing only IT key skips a subject Prints out the ranking list by class the whole school average variance and frc 1uency distribution upon completion of the class processing I With the scores of two classes for five subj...

Page 148: ...of all school Frequency distribution shown by the average marks of five subjects Up to I0 classes can be handled 2 Input items necessary to make the frequency distribution are as follows Interval 10 Start point 0 Number of intervals 5 Only when the start point begins with 0 the difference between the first and next start points is Interval I The number of intervals is up to 20 Make the file by the...

Page 149: ...ST SCIENCE TOTAL 150 AUG 30 100 100 100 100 100 100 100 80 90 60 80 90 40 78 80 50 45 60 70 55 10 25 60 35 20 CLASS TTL 1728 CLASS AVERAGE 69 UARJANCE 741 25 Do no sa e M ERlT ORD ER 888 CLASS LI ST 1 MN N LANG MATH ENG HlST SCIENCE TOTAL 475 AVG 95 2 ST N LANG MATH ENG HI ST SCJEN CE TOTAL 360 AVG 72 3 QR N LANG M ATH ENG HlST SCIENCE TOTAL 355 AUG 71 4 KL N LANG MATH ENG HIST SC IENCE TOTAL 260 ...

Page 150: ...arks IDE J1D J INTERVAL OF lllSTOCRAM 2 5 I TE I START POINT 3 0 i un I NO OF INTERVALS 4 20 I Key Operation Procedure 2 Step No Input Display Remarks 1 lo I CD REGISTER l CHANGE 2 I 2 I L ENteR I CLASS NAME 3 AAA NAME 4 AB r 1 NAME Repeat 9 lJ I I NAME Processing is over wi1h this 10 TAPE OUT OK l N0 2 key If OK 111 then iII be 3 cd in10 lhc UlJ C 11 2 fHT Do not sale this PDF 144 ...

Page 151: ...on display 2 2 EJ TER I I AR start to enter a S Orc of each subjec1 with this key 3 I EHTEA I N LANG O When it s lhst 4 80 I EJ TER I MATH O 1in1e 0 mark is displayed 5 90 I ENTER I ENG m s _ 6 40 EJ TER I HIST O 7 78 l ENT I SCIENCE O 8 80 l EHT I 2 CD 9 I ENTER I N LANG 0 10 I00 I EHTER I MATH 0 Repeat 37 70 I NTER I SCIENCE O Set the cassette to 38 55 IENT I TAPE OUT 0K l N0 2 Sfi IC in 39 I I1...

Page 152: ...E IN OK 1 N0 2 2 2 jl JfT R I WHOLE OK 1 N0 2 Prints the list by class Input 2 since not 3JI classes 3 2 I l lfTI J are ovec Repe3t cul TI to IDffl m by 1henumber ofclasses 1 1 1CD TAPE IN OK l N0 2 2 2 Il XT0t I WHOLE OK J N0 2 _ Prints the list by class Upon complelion of all classes inpu t I 3 I I 111n I The average mark of all and frequency distribu lion arc prin1ed 0111 Do not sale this PDF 1...

Page 153: ...BBB I I CODE Class List is printed out 5 5 IEHTER l NAME New 6 KL 1 El TER CODE 7 I EHTER I TAPE OUT OK 1 N0 2 _ Processing is over with th is key 8 2 1 EHTER I 1 ouj 0 TAPE IN OK 1 N0 2 Correction of Marks 2 2 1 ENTEA j I KL 3 Mark before correction is N LANG 90 displayed Enter nc v score if need cd 4 I I MATH 95 _ 10 be modified and pre ss this key with no input if no correction is necessary 5 9...

Page 154: ...S 1 325 INT CF A Q 5 330 6 1 60SUB 800 335 INPUT WHOLE 0 K N0 2 E 340 IF E l E 2 GOTO 335 345 IF E 2GOTO 365 350 S J NT CC O SJ LPR INT AUG OF ALL S LF l 352 R 0 FOR J 0TO 0 1 R INT CO J SJ 2 R Nf XT l 353 JF O LF 2 GOTO 360 354 N R 0 J N INT CN l l0 3 t 5 J01 3 355 LPRINT UARIAN CE N LF 2 360 60SU9 900 365 END 400 0 CLEAR P 4 4 0 4 K S 0 IM 8 P B O I Pl 0 CQ t9 O K 41 0 0 C0J N LANG OS I M ATH 0 ...

Page 155: ...N XT 1 845 IF G 0GOTO 860 850 LPRINT CLASS TTL F 855 R 0 LPRJNT CL ASS AVERAGE M C c n IF K O LET O O ll M 85 FOR 0 0 TO A 1 S INT B Q I 0 Q J 5 R S M 2 R NEXT 0 858 IF A JGOTO 860 859 N R A J N INT N 10 3 5 J0 3 LPR INT VARIANC N 860 G 0 LF 2 RETURN 900 LPRJNT HISTOG RAM Do not sale this PDF 903 GRAPH GLCURSOR 0 0 SORGN LI NE 50 0 2 15 0 LI NE 0 0 5 0 450 905 S E 0 F OR 1 1 TO V J IF S E l LET S ...

Page 156: ...otal cs DS Pl Subject names D No of Classes OS D K Class averages Counting the number of E ES E V l students in frequency distribution F Class Total FS F V 1 Figure of start point at each interval G GS H HS I 1 J JS K No of Classes KS L LS M Class average mark M N NS 0 0 p MAX no ofstudents PS in Class a No of subjects as R RS s SS T Interval TS u Start point U v No of interval VS w Individual ave...

Page 157: ...egistered schedules 0 Used t o print the first schedule after the designated date 0 Used to print the Jocked or unlocked schedules GJ Used to delete the designated schedule 0 Used to delete the schedules before the designated period except for the locked ones Q Used to loud the schedules from tape CD Used to save the schedules to tape Cautions I The program stops when pressing the lau key Press th...

Page 158: ...g the 1 1 key to stop the program 2 Clearing all schedules by the IDE I 0 operation 3 Pressing the ID FI CTI keys to start the program 4 Pressing the 0 to register the schedules Visitor from 10 00 December 10 to 12 00 December 10 with an alarm 30 minutes prior Unlocked Party from 18 00 December 24 to 23 00 December 24 with an alarm 60 minutes prior Locked 5 Pressing the W keys to print the first s...

Page 159: ...0 ENO J2 24 23 00 STOR T J 30 6 30 ENO 11 13 16 30 LARM 60M JN PRJOR ENO J 1 30 5 50 ALARM 30MIN PRIOR A LARM 0MIN PRIOR t GYMHt ST l START I l 30 6 30 UNLOCK LIST ENO 11 30 6 50 rn Rn 0MJN PR JOR UJSJ TOR t srnRT 12 10 10 0e ENO 12 Jei 12 00 ALARM 30MIN PRJOR I Key Operation Procedure 1 StopNo Input Display Remarks 1 ID 1 ITJ AJI schedules cleared DELETION END 2 joEF I IT 11 5 16 03 Program start...

Page 160: ...RM TIME Schedule contents i1 t 1 larrn tin1c input minutes 19 20 IENTER I LOCK UNLOCK 2 prior to I IENTER I Selection 20 Returns to the display at che seep 9 21 TI LIST START DATE Month and day inputs in 4 digits Month and day inputs in 22 1115 IENTER I us1 END DATE 4 digits Prints out che schedules 23 1120 IENTER I registered then continue program Prints out the schedules 24 0 11 10 9 30 for the ...

Page 161: ... Returns to the display at I 15 I IEHWI I the step 4 Month day hour and m DATE TIME minute inputs in 8 digits 2 digits each 16 Prints all the schedules t2150000 I NT I after the input date and continoes program 17 m LOCK I UNLOCK 2 LOCK Selection UNLOCK 18 I I EHTEA Prints all the locked sche dules and continue program 19 GJ LOCK I UNLOCK 2 _ LOCK Selection UNLOCK Printsall the unlocked schc 20 2 ...

Page 162: ... 1 1 1 Stops program 2 DEF mi DELETION END Clears all schedules loul ITJ 11 10 9 05 Reads schedule saved in 3 Example I 4 CD TAPE IN OK YfN _ Month day hour and min ute inputs in 8 digits y NtifJ SCHUDELE Display of file name 6 11 I0 9 10 6 m DATE TIMfl _ Month day hour and min ute inputs in 8 digits Re runs program after deleting the schedule 7 11250000 I DELETION END other than the locked be for...

Page 163: ...0 IF Y XGOTO 200 212 FOR J 0TO 25 IF X P J 0 GOTO 220 216 IF X P J I GOTO 222 21a z 1 J 26 GOTO 222 220 IF Y P J 0 LET Z J J 26 222 NEXT J 225 IF Z ILET Z 0 GOTO I75 226 P I 0 X P I I Y CLS INPUT CONTENTS N J CLS INPUT ALARM TIME PC J 2 235 CLS INPUT LO CK l UNLOCK 2 P l 3 JF P l 3 1 p I 3 2 1GOTO 235 240 NEXT I 245 IF U ILET U 0 GOTO 290 250 H 0 K 0 255 FOR J 0TO 25 IF P J 3 1 GOTO 275 265 lF P J...

Page 164: ...ET 1 2 6 NEXT I GOSUB 900 60TO 725 720 NEXT I 725 60SU8 920 CLS RETURN 750 M G il INPUT DATE TIME G FOR 1 0TO 28 IF G INT P J 0l 1 00JGOTO 77 5 7 70 GOTO 790 7 75 IF P I 3 2 GOSUB 900 780 NEXT J GQSUB 9 20 CLS RETURN 800 N CLEAR OJM P 29 4 N 29 i 40 GOSUB 920 ENO 830 Z WAI T 0 836 FOR R 0TO 28 837 A TIME GOSUB 950 PRINT n 838 8 JNKEYS IF 8 8 8 C 8 a 0 S F BS G 8 1 H J GOTO 842 839 IF 8 M B K 8 1 A...

Page 165: ...NS iJ Contents 946 GOTO 945 H Pli 0 Start time 94 8 l F E 59GOTO 94 s I P i 1 End time 949 RETURN J P i 2 Alarn tirnc 950 8 1 NT CA 10000 C INT A 81 K P i 3 Lo k unlock 10000 100 0 Before or after of INT A 01 10000 L P i 4 C1 100 M the current time 955 E NT l l B I 0 000 C1 100 D l N 00 0 9 5 IF E 0LE T ES 00 GOTO 980 p 9 6 ES STRS E Q 980 AS STRS B STRS C R STRS O Es s 985 RETURN 990 LF J LPR INT...

Page 166: ...pe I Purchase ledger New Supplier A 123 Product name A 11 C 33 D 44 Price 1 000 5 000 1 000 Quantity 15 5 I Key in the above according to the Key Operation Procedure With END Y N displayed type in Y Using the ID 1 0 keys enter the next data At this time replace the tape with a new one New Supplier J 963 Product name J 77 Price Quantity Key in the above in that order 6 200 3 With the display of END...

Page 167: ...uantities for the same product name are summed up in the list Registrations can be up to 140 product names per supplier Printout PURCHASE LEDGER liPURCHASE LEDGER LJST t A 123 A 123 J 963 A A 1I T 77 a 1 000 a 1 000 8 6 200 15 t 15 3 IS 000 15 000 l 8 600 C 33 a 5 000 C 33 TOTAL II 5 000 I 81 600 35 000 5 0 44 2s 00 II 1 000 A 123 2 0 44 C 33 2 000 8 1 000 8 5 000 R 55 t l 2 II 4 000 11 000 10 000...

Page 168: ...completed for this 13 I l PRODUCT I AME supplier 14 tR TAPE OUT OK Y N Set cassette tape 10 SU e 15 y I HTEIO I END Y N y J Total t y pplier is print 16 ed 17 JoullIJ END Y N 18 N I HT IO I NEW Y N 19 y 1 1 SUPPLIER 20 J 963 I EHTEi PRODUCT NAMEe 21 T 77 C rll0j PRICE 22 6200 1 11 QUANTITY 23 3 I I PRODUCT NAME 24 r Ll TAPE OUT OK Y N Set cassette tape to sn c 25 Y f EHTP j END Y N Tape for this s...

Page 169: ... 37 y EMT I END Y N 38 y EHTtR j 39 o SUPPLIER Repeat 40 A 123 IEHT I TAPE IN OK Y N Se1 cassette tape to load y IENTt I 4 1 SUPPLIER 44 IEHTEA l End I Program List I 5 A CLEAR 20 CLS INPUT SU WAIT 0 PPL JER jA 10 0JM 8 139 O GOTO 27 139 8 139 25 GOTO 2q5 I 1 LF 2 2 IF Y Y GOTO 12 USJNG LPRINT 80 PURCHASE LEO 30 I NPUT TAPE I N GER OK Y N j X 3 INPUT ENO Y 40 JF XS Y GO TO N ws 30 14 IF W Y GOTO 5...

Page 170: ...ltl litltl 635 E B l D I N D J GQTO 21 640 LPRINT BSCI 0 645 LPRJ NT El 0 200 LPR NT j USING tiIiIIII litl II p USI NG tttttltllltltl tllltltltttttt l l N i 0 1111111111tttt t1t1t1 r J a 210 LPRINT S 650 LPRINT B l 215 LPRINT E R 216 LF I 652 LPR NT E Quantity 220 F F E 655 F F E s for this time 225 IF Z ILET D ll 660 NEXT I O J B I B I 680 GQSUB 900 Price S GOTO 240 685 G G F F 0 T 22 0 l T BC l ...

Page 171: ...tape has only one customer Example I 1 Dilling ledger new customer Customer code G 55 Product number K 33 H 66 Price 2 500 1 000 Quantity 6 5 Type in the above data according to the Key Operation Procedure shown later When END Y N displayed type in Y Use the loc I IT keys again to enter the data of another customer Again make sure to replace the tape with a new one for the new customer New custome...

Page 172: ...ies for the same product are summed up in the list Up to 140 products per customer can be handled Printout BILLING LEDGER G 55 Z 99 H 66 K 33 G 55 f fil 1 000 ii 2 500 K 33 6 q a 2 500 6 000 10 000 6 TTL J5 000 J 7 10 000 a 3 500 H 66 2 GTTL a 1 000 000 43 000 5 5 000 TTL 13 000 TTL GTTL 20 000 23 000 GTTL 20 000 BILLING LIST G 55 BILLJNG LEDGER K 33 a 2 500 2 99 6 K 33 15 000 ii 2 500 H 66 4 a I ...

Page 173: ...Rl TAPE OUT OK Y N _ Set casscue tape for sav ing 12 y I ENTER END Y N All inputs are completed 13 y I E N TER To1al by cus1omcr is printed 14 0 ENO Y N _ 15 N EXTER I NEW Y N 16 Y I EHTER CUSTOMER CODE I 17 Z 99 IINTER I PRODUCT CODE 18 K 33 I rHTER I PRICE 19 2500 I NnR I orrv 20 4 I NTER I PRODUCT COO i Input is completed for this customer 21 I EXTER TAPE OUT OK YIN Set cassette tape for sav in...

Page 174: ... CUSTOMER CODE 41 IENWt I End I Program List I 5 A CLEAR 30 1NPUT TAPE IN 150 INPUT PROO c WAI T 0 OK Y N x ODE 8 Cll Z 10 DI M 8 139 0 0 GOTO 165 139 B 139 40 IF X Y GDTO 160 GOTO 245 11 LF 2 30 65 1 NPUT PRICE 12 USI NG LPRINT 5 0 INPUT llA 8 T BILL ING LEO D B 170 1NPUT 11 QTTY GER 80 LF I s 13 INPUT ENO Y 140 U SI NG LPR I NT 190 E S T N W U II j f j t 195 LPRINT 8 1 14 1F W Y GOTO 143 FOR 1 0...

Page 175: ...T OK CY N 750 ENO J Xt 900 LPRINT T TLI 246 IF Xt Y GOTO 910 LPRJNT USING K 245 1111111111111111111111111111 L 250 PRINT llAt Bt l 111111 F 0 8 l 915 LF l M 260 FOR 1 0TO N 1 920 RETURN N v 265 8 0 950 LPRINT GTT 0 0 8 0 L 270 NEXT l 960 LPR JNT G p 300 GOSU8 900 970 RETURN 0 320 G G F 325 F 0 R 330 GOTO 13 Quantity for this 390 GOSUB 950 STATUS l s time 400 ENO l 320 500 B CLEAR T Price for this ...

Page 176: ...h is printed out in different colors for in dividual factors Example I Type in the followings Desired month 1981 July Name SllARP Dateofbirth 1952 I January 28th Contents Formulas Input Desired month Name and Birthday Output Printout of the biorhythm curves for the desired month Ist to 31st in different colors for individual factors Calculation is made for the X axis values of the curves as follow...

Page 177: ...81 7 NAME SHARP BJRTH 1952 1 28 PHYSJCAL EMOTJONAL JNTELLECTUAL 5 10 15 20 25 31 Key Operation Procedure Step No Input Display 1 l I DATE YEAR 2 1981 I EHTEA I MONTH 3 7 I ENTER I NAME 4 SHARP i EHTEA I BIRTH YEAR 5 1952 IENTE I MONTH I I ENTER I DAY 6 28 EHrE I Do not sale this PDF 171 PROGRAM NO PS E 1 Remarks 4 digit input 4 digit input Printout 2 ...

Page 178: ... 260 L INE 90 Yl J J 5 y 270 X 80 290 Z Y S 300 LINE JIS Z x 2 9 3J0 LPRJNT R 320 NEXT Q 330 B INT CA 23 J B A 23 B 340 C IN T A 28J C A C28 C 350 0 1 NT CA 33 0 A 33 0 360 FOR J JTO 3 39S COLOR J 400 E 0 4J0 FOR Y 0TO I 420 IF J 2LET X SJN 8 YJ 23l 360J 80 430 IF J 3LET X SIN C Y 28l 360 80 440 IF J ILET X SIN D YJ 33l 360ll80 450 Z Y J l2 5l5 460 F 0 470 IF E 0LET F 9 LET E l 480 LINE 0 P X Z F ...

Page 179: ... the cycles a Loop counter Physical R Index No of days Set the remainders s after divUion ofthe T c iota number ofdays u by the cycles v Emotional w Set the remainders x Biorhythm curve afler division of the X axis D Iota number ofdays y No ofdays per monlh by the cycles counter Intellectual z Biorhythm curve e First judgment Y axis F Pen up down code A Name G H Corrqp0nding I month and the number...

Page 180: ...One player can bet his points on up to S combinations of boats and I to 9 bet points on each combination The bet points are pooled if nobody wins the game and the pooled points are allocated to the winner in the succeeding game I Example 1 The boat race game is played by two people One named JAMES Boat combination of 1 2 The other named FRANK Boat combination of 3 5 Contents I Formulas I Boats mov...

Page 181: ... fXTEA I NAME _ Input the name 5 FRANK NTEA 6 ou JAMES lllpul the data by player DO YOU BET Y 1 Do you bet any points 7 y IENT I COMBINATION Inputs the combination of 8 1 2 I ENTER t BET POINTS 1 9 1 2 If no more bets press 9 5 I ENTER I COMBINATION only Ie r I 10 EHTE i I FRA IK Next player DO YOU JlET Y N 11 y I ENTER I COMBINATION 12 35 EHTt I llETPOINTS 1 9 13 7 ENTER I COMBINATION 14 I NTER I...

Page 182: ...RNO J IF L XGOTO 350 353 E 2AL P RNO 2 J 35S GCURSOR CCJCLJ J 360 FOR l CICL l TO CJ L P QJ POINT JOR E GPR JNT QJ NEXT I 355 CJ L CJ Ll P 390 IF CJ L J 80 GOTO 350 400 BEEP J 90 50 BEEP J 0 50 402 8EEP 1 150 90 BEEP J 150 100 404 BEEP J 50 60 BEEP J 250 J50 410 IF X 999LET X L GOTO 350 420 Y L J X X J 490 WAIT l00 USJN6 CURSOR JS PRJNT X STRS Y S00 S J0fX Y J l0f Y X SJ0 Z 0 Gl 0 01 0 520 FOR A I...

Page 183: ... Winning OS Points E ES Ct S Ooat Position F F G Individual Losing G G1 Total Losing Points Points H HS I 1 01 Total Winning Points J 2nd 1st Combination J K Competition Rate KS Z 1 Used in letter string L LS M MS N No of Players NS 0 OS p Boat Speed P Q 0 R RS s 1st 2nd Place S Combination T TS u Ca rryovcr Point U v VS w ws x Winning Boat No XS y 2nd Place Boat No YS z Total Bet Points ZS Do not...

Page 184: ...splayed The instmctions for Replay are displayed after few seconds With the elapsed time on display the time for the present game and the short est time up to now are indicated Press the Yes to restart a game and the 0 No to end the game Contents I Formula I Selects three labyrinth patterns I 05 dots by using random numbers I to 12 for display After a few seconds the masking pattern All are 7F beg...

Page 185: ...e left 1 lo I 0 labyrinth pattern is masked The moving dot Oashcs and the time counter dashs for time di play CD QJ The movement designation m moves the dot m The wltltc on black passage Cheers mark and the elapsed time are displayed YOUR TIME Stays for 2 or 3 seconds The shortest lime ii di SllORTEST TIME played Stays for 2 or 3 seconds REPLAY Y or N Replay or completion OR CD f EHTER I To step 2...

Page 186: ...4 l 7F405 F51S07 077C077 940575A55755DZ 77 l50477A097F2 J6F08 44 T 1 0 J 2A6F5 l 5f547Bl23F4A B 44 F445Dl l 772B 700A7F027F14 5 41SF712F 48 F48 297F08 45 T 1JJ 296F2 J 306 3057S0417F 105F 457E55257D 2A6B097F0J7005 75555F407F027F J07F08 50 A RNO 12 B RND J2 C RNO 2 60 IF A BGOTO 50 61 IF A CGOTO 50 62 IF B CGO TO 50 0 CLS A A J S B l C C l 80 GCURSOR 0 6PRJNT TS A T 8 T C l 8 J BEEP 0 J0 I0 J00 FOR...

Page 187: ... l 150 90 624 BEEP l 150 J00 625 BEEP l 60 60 626 BEEP 1 200 200 630 T TlM E T T INT T T TtJ000 0 640 MM INT CT J00 SS T CMM1 l00 645 NPS STR MM STRS SS 650 WA1T J50 CURSOR 2J PRINT NPs 660 lf M MMLET M M M s ss GO To 10 0 6 0 IF M MMGOTO 00 680 IF S SSLET S S s 700 CLS CURSOR 0 IJA lT 0 Do not sale this PDF 710 PR JNT YOUR Tl ME 720 1 JAIT 150 CURSOR 12 PRINT NPS 30 CLS CURSOR 0 IJA IT 0 740 PRJ ...

Page 188: ...cal Shift Dot Position E ES PW Horizontal Shift Dot Position F FS MM Elapsed Time Minute G GS SS Elapsed Time Second H H NPS Elapsed Time Editing Data I 1 HP Shortest Time Editing Data J JS TS 1 Dot Pattern Table K K IL LS Shortest Tin1e M M Minute N NS 0 OS p P 0 OS R RS s Shortest Time SS Second Time Calculation T TS Value Min Sec u us v vs w ws x Present Point Pattern XS y Present Point YS Your...

Page 189: ...perations The Jess the better 2 lo I The display becomes the same as that already shown in 1 1 GJ It is a lot of fun to compete with others for the most efficient and quick alphabetical rearrangement Example I 2 3 4 5 6 7 8 9 lf lHIBlf l IAlcl Jl J I 2 3 4 S 6 7 8 9 FIEIHIBIAlclJlnlcl ii I 2 3 4 5 6 7 8 9 FlttlnlAlcl 1lolcl 1IEI For example if the breakpoint 4 is input in this letter string the al...

Page 190: ...ntil the loal CD alphabet is stored A toJ Random order 2 m m Press any one of the break Repeat points I to 9 I A 10 J Rotated alphabets on dis play 3 GAME END Displayed when the alpha bet is rearranged in correct sequence YOUR SCORE The score is displayed The letter string first dis IouI m A to J Random display played in the IouI Q appears and the procedure returns to step 2 Do not sale this PDF 1...

Page 191: ... PR JNT USJNG L SS M POJNT J60 CURSOR 20 J65 C 0 N Score 1 0 lNPUI c 0 I90 JF C J G OTO 140 p 200 F C 3GOTO J4El 2J0 K LEFJ C Q 220 L RJGHT CS R Random number 10 C s v 240 IF C lGOTO 260 250 l RJGHU CK T l LEFT K C J u 260 JF C 9GOTO 280 v 270 L RJGHT u s 9 C LEFT 1 L w 280 S KS L x 290 N N J y 300 IF S t DSGOTO 140 z 3J0 BEEP 5 CLS USI NG PAUSE 0 ABCDEFGHIJ GAM E END KS Randomly ordered 320 WAJ T...

Page 192: ...re key 2 You can get 2 points if you bang the mole in the first stage I point in the second and no points in the third You Jose 2 points if you strike where there is no mole 3 As the game continues tlte mole moves slightly faster 4 When you fail to strike the mole four times the game is over I Software Keys W G W OJ 0 OJ I Contents Finding the mole display positions I to 6 randomly raise the displ...

Page 193: ...OGRAM NO 2 TI T LE PS E 7 Key Operation Procedure Step No Input Display Romarks 1 l L GAMESTART IT Mole display in 3 stages Press the nearest soft ware key immediately after a look 0 _ _ 0 0 LD Score Dis play GAME OVER SCORE The game is over Score Display Do noTsaTe tnis l 1DFTIT 187 ...

Page 194: ...1 10 GOTO 160 420 IF R 2GPR1NT 150 GOSU8 400 20J03C7C7C3CJ0 L 160 WA 1T 0 6CURSOR 20 T T J 60TO M C GPRJNT 0000 440 000000000000 430 IF R 3GPRlNT N 170 J r F J 20 i 33F 7E7E3F J 0 72 lF X 3GOTO 600 20 174 JF E 0LET W I 440 PR JNT T Mole Display Posti GOTO 60 450 RETURN p tions I to 6 I76 IF F 0GOTO 600 500 IF R lLET T T 180 GOTO 60 2 GOTO 530 a 200 C l0 P J t 24 510 lF R 2LET T T GCURSOR C 1 GOTO ...

Page 195: ...e counts down by 5 points 3 When the spaceship hits a meteorite an explosion is displayed and an alann sounds The game is however restarted I Contents I I The randomly selected one to two dotted meteorite pattern per row is stored in the meteorite display pattern table One to 100 rows are to be housed with an alann sounding for each 2 After the display of the housed meteorite pattern table content...

Page 196: ...LEAR J60 CURSOR 22 20 0JM TU01 PRJNT s RANDOM 170 P 0 0 1 30 1 JAJT J00 PRJ NT 190 FOR J I TO 2 GAME START IBJ JF P l00GOTO 5 40 FOR N ITO 100 00 STEP 2 190 At X 0 1JAJ T 50 A RNO 7 8 2 A 2 J 200 A T B AOR 0 60 JF A l A 7 210 GCURSOR P JLET T N B GPRJNT B BEEP 1 1 l 220 A JNKEYS GOTO I I0 230 l F A GOTO 70 C RNO 7 300 80 JF A CGOTO 70 250 GCURSOR P 90 C 2 C I GPRI NT A 100 T N BOR C 260 A INKEY BE...

Page 197: ... P J 3 0 30 CURSOR 22 J PRJNT S GQTO K 80 L 370 A P 4 F A J LET A M 380 B EP 5 J0 J0 3 l0 W Al T 70 Loop Counter for GCURSOR A N meteorite patlcrn GPRJN T 0008 A storage JC7FJC2A0800 400 WAJT 0 S S 6 0 CURSOR 22 p Display Posilion PRJNT s 4J0 FOR E ATO A J0 a 415 F E l0J GOTO 4 R 40 s Score 420 GCURSOR E GPR JNT T E T Meteorite Patlern 430 lEXT E Table 440 P P J GOTO J80 500 WAJT J50 u GCURSOR J05...

Page 198: ...t The time limit depends on the number of letters displaged and the exercise grades I 2 3 Grade 1 is the shortest and Grade 3 is the longest Ten typing exercises in each grade Challenge to the perfect score of 100 I Contents I The number of letters 3 to 6 is determined by using random number generating function The letter string A to Z is also extracted by using same function I Key Operation Proce...

Page 199: ...de Y Y CHR 0 M 40 NEXT c 0 CLS BEEP 3 N PRINT Y 0 CURSOR 10 E 0 B0 FOR W JTO Btl0 p Score t L B CE No ofcorrectly typed JN KEY IF B a letters E THEN 100 SS PRINT 8 R 90 E E J IF E B s No ofexercises LET IJ 400 J00 NEXT IJ Q 0 T JI 0 FOR IJ 0TO 8 J u IF A 1J 8 1J LET Q Q J v J20 N EXT W I F Q R w Time THEN J50 I30 IF Q BLET P P x Highest score 10 60TO J50 Letter stringof ane x J40 P P S y l50 N EXT...

Page 200: ...is program make sure to set the built in clock TIME correct lDEFI lIJ With the f s key pressed the elapsed time is displayed in the form of OM OS 2ssl Pressing again the I key displays the elapsed time in the form orjSTOP IOM 59S 4SSJ to complete processing 0 Qi l Type in 003000 for the time when set to 0 hour 30 minutes 0 second Pressing the key displays the elapsed time in the form of ITIME LAPS...

Page 201: ...ut Display Remarks Type in 1hc ourrcnl lirne TIME I0 5350 E ITER i I 0 5350 10 53 50 2 o J m ALARM TIME Designalc 1hc alarm 1im e 10 57 00 3 105700 ENTEft NOW TIME IOH53MS6S Current lime being dis played 4 NOW TIME IOH57MOOS Alarm sounds 20 1hncs OJ TThfER Designate 1 he clmc Sec 1 the lime aflcr 00 30 00 2 003000 J EHTER I TIMER 003000 3 I ACE J TIME LAPSE OH OM 1 4 TIME LAPSE 011 30M OS Alarm so...

Page 202: ...O 300 30 U U 2 Timer Time Elapsed 200 Q N 35 A 0 A 0 N Time Now 210 GQTO 60 40 IF U J0LET S S 300 ENO 0 A 0 0 Elapsed Time Old q00 D CLtAR 750 IF U 10LET S S WAL T 0 I U 0 p 410 INPUT T lMER 60 IF S 60LET n n a N 0 A 0 4I5 GOSUB 900 70 IF S 60LET M M R 420 U Ht60 2J n i S 0 60 S 0I0 PRJNT M M s Tl111er Time Second 440 S 0 USI NG Utitt S T 445 A 1 S11 USING ll tl 450 AS I NKEY U SS Timer time con 4...

Page 203: ...on Stop Watch Function A A W ORK B B c c D 0 E E F F G G H Current Time Hour H Elapsed Time Hour I I J J K Calculation K L L M CurrentTime Minute M Elasped Tine Minute N Elapsed Tune Now N 0 Elapsed Time Old 0 p p a a R R s Current Time s Elapsed Time Second Second T T Alarm Time Elapsed Time 1 10 u u second v v w w x x y y z z AS INK BYS Do not sale this PDF 197 ...

Page 204: ...ssing the luul iJ enables the printout of a cute flower design Contents I Formulas X i Sin 6 x i x Cos i A x 80 Y i Sin 6 x i x Sin i A x 80 Changing value of i from I to 30 per petal 30 coordinates an connected with lines Changing value A from 0 to 330 twelve times in 30 increment finds the coor dinates of 12 varied petals Printout I The actual printout is colored Refer to page 4 Key Operation Pr...

Page 205: ... I E 60 XC SIN 611 1 J CXCl 2 Y F l COS HA l B0 J 2 C XCl 3 70 YU SIN 6 11 I YCH3 l G S IN CHA BB 320 NEXT I H 80 N XT l 330 RETURN 90 GQSUB 110 11 Variables of FOR 100 NEXT I I statemen1 105 COLOR 2 110 FOR l JTO 30 J 120 X l SIN 6 1 STATUS I 50 589 K J30 YCll l 5 L J40 N fXT 1 150 GOSUB p M 155 X XC30 Y YC30 N J50 LlNE CX 40 Y 0 X 40 Y I0 0 0 B p J70 LJNE C X 35 Y J Q 0 C X 25 Y 60 X 25 Y 60 C R...

Page 206: ...e I Ex I Geometrical pattern with I0 degrees 3 5 increment and 30 triangles Refer to Printout Ex 2 Pattern with 20 degrees 3 increment and 35 triangles Contents R R K Formula R is sum of increments and its initial value is 5 Value K is added to each pattern T T S Tis sum of angles and its initial value is S Value Sis added to each pattern XI RX S int Yl RXCost X2 RX S i n T 60 Y2 Rxc os T 60 0 0 X...

Page 207: ...ist Memory Contents I l 0 A GRAPH A RANDOM lncrc111cn1 input 20 GLCURSOR J20 K 200 SORGN L 30 lNPUT NO OF M TRlANGLES iN No of Triangles 40 INPUT ANGLE N S input 50 JNPUT INCREME 0 NT K 60 T S R 5 p 70 fQR l lTO N Q 75 COLOR RNO 4 1 R Increment Calcula 80 R R K T T S ted value 90 Xl R SlN T Yl s Angle input R COS T 100 X2 R SlN T 60 Angle Calculated Y2 R COS T value 60 110 LlNE 0 0 XJ Xl Graphic X...

Page 208: ...REMARK Japan time can be easily found as follows Suppose you live in New York Japan time is 14 hours ahead as derived from the tim difference tablc shown on the next page If it s 7 00 in New York it s 21 00 i11 Japan 7 00 14 00 21 00 Change the sign of your time difference from Tokyo and add it to your time tlowevcr when the sum becomes more than 24 00 th e day should be the next day in Japan IT P...

Page 209: ...4 DELHI 3 30 24 HONOLULU 19 5 CHICAGO 19 15 NAIROBI 6 25 ATHENS 7 6 LONDON 9 16 AUCKLAND 4 26 CAPETOWN 7 7 PARIS 8 17 MOSCOW 6 27 BERLIN 8 8 ROME 8 18 CAIRO 7 28 MELBOURNE 2 9 VANCOUVER 17 19 TEHRAN 5 29 ABUDHASI 5 Note Standard program includes 8 cities from No 0 to No 7 T he expanded program includes these 30 cities Key Operation Procedure I Step No Input Display Remarks 1 TIM E 1102 01 46 I ENT...

Page 210: ...SUB 500 80 IF t 28GOTD 9 M Hour for each city 3 0 GOSUB 650 60 N Minute for each cily 380 BS INKEYS 90 IF K l 3 390 IF BS GOTO 3 CK Sl CK 0 0 K 8 K 10 K v 400 IF BS 8 GOTO 12 1LET Z 31 p 30 GOTO 8 10 Q 4J0 1F 8 2 GOTD 800 IF K 2LET 2 28 460 GOTO 840 R 420 GOTO 3 0 810 Z 30 430 01 1 l l 1 840 IF L ZLET L L s v 4 10 IF J 0LET 1 1 Z K K J P l 860 IF K 12LET K K T 450 GOTO 360 12 u Number 460 01 I l I...

Page 211: ...0 3 0 60SUB 650 380 8S I NK Y 390 IF 8 GO TO 3 70 400 IF 8S B GOTO 430 410 IF 8 2 GOTO 460 420 GOTO 370 430 OJ J 1 1 J 440 IF J 0LET l J P I 450 6QTO 360 460 0 I J I J J 470 IF J PLET J J P 1 490 GOTO 360 500 CLS US ING PRl NT US NG 8 8 8 8 8 8 8 8 8 AS J 520 Y ACJ F Y 0 LET X JNT ABS YJ GO TO 54 0 530 X INT Y 540 Y CY X tl00 550 G TIME 560 C INT CG 10000 5 0 0 NT G J00 Ctl00 SB0 1NT G C tl000 0 0...

Page 212: ...e program 3 0 100 columns are available for patterns 4 Remark Normal key operation causes a beep tone to confirm the entry With a key pressed other than specified two beep tones warn the key operator When the dot range is going to exceed the specified range three beep tones occur to give warning Contents Formula Processing is perfonned in respones to the numeral keys and mode setting keys 2 When s...

Page 213: ...Tl The dot moves down wards CD The do moves upwards L J The dol moves 10 the right ITl The dot moves 10 1he left This key is designa1cd when 0 MOVE moving the dis1 laycd dot while ii is being erased This key is designated when Q TRACE moving the d while lcav ing it at the displayed p Sition PRINT Pattern prin1out CD Ends prograrn Printout I The actual p rintout is colored Refer to page 4 l Q r nin...

Page 214: ... GO TO 50 255 A YOR O W 56 GCURSOR P GPRJNT A D DIJ GOTO 50 260 JF PtJ 0LET PW 0 BEEP 3 l 0 20 GOTO 280 270 JF PW NLET PW N BEEP 3 10 30 280 IF M OOE 0GOTO 286 284 6CURSOR P GPR JN T Y GOTO 290 2 B6 A 7F Ol A A ANO X 207 GCURSOR P G PR JNT A 290 P PW D OJ 6010 50 300 GCURSOR P GPRJNT X 0 01 0 30l TS l23156 89A BCDEF 305 G RAPH f LCURSOR 0 0 3J0 COLOR ROTA I CS JZ J 320 C J l 0 330 FOR J JTO 340 A ...

Page 215: ...on or cs PW Cursor Position Save the printer during movement D Moving Dot Position OS Print Data MODE Mode Save Cursor Stan Point of E the printer ES F FS Hexadecimal Code Upper digits G GS Hexadecimal Code Lower digjtS H HS I v IS J JS K KS L LS M MS N Dot range used NS 0 OS p Cursor Position P a as R R s SS T TS Hexadecimal con version table u us v vs w WS x Present Pauern XS y Present Pattern v...

Page 216: ...words from the cassette tape ind also outputs them to ihe cassette tape I Data registration correction Input approximately ten data 2 Translate native words into foreign words Input the spelling 3 Translate foreign words in to the native 4 Switch the order of word appearances S Store data into ihe cassette tape and load the data from the cassette tape 6 Data list and output I Example I Suppose the...

Page 217: ...he corresponding Japanese or N in case the corresponding Japanese is unknown to you c To input Y The following English word MOON LIGHT for GETSUKO is diaplayed To input N The Japanese MATSURI for FESTIVAL is displayed Contents Formulas Up to 16 characters of a native or a foreign word can be registered in the standard capacity of PC 1500 The pairs of foreign and native words which can be registere...

Page 218: ...STRIBUTE I ENTER I N LANG JO s BUNPAI SURU I ENTER I ENTRY END Processing is over 9 8 IENTER I GRASS CHANGE Y N 10 N l T R I UP DATE NO to step 9 Y j ENtER I F LANG to step II I ENTE RI Modification is over 11 GRASS IE NTER I N LANG KUSA IEN TER I UP DATE NO to step 9 Key Operation Procedure I Step No Input Display Remarks 1 joEFj CIJ MATSURI 2 HESTIVAL IENTER I MATSURI F Wrong input 3 ESTIVAL I E...

Page 219: ...apanese words registered in this program Program List I 5 C WA I T 0 CLS 90 AS N L ANG 4 200 CL S IF CAS Y 10 JNPUT ENTRY S TRS CA N l l l UP DATE E UJ GOTO l 80 A 100 CLS PRl NT AS 210 I F AS N GO TO 20 F CAS E J A I J0 JNPUT J J 150 U JGO TO J20 NEXT J 220 I NPUT F LANG J0 13 0 PAUSE ENTRY E ES A ll 30 IF AS U GOTO ND 230 1NPUT N L ANG J50 140 ND JS A l 40 CLEAR JNPU T 150 INPU T UP DATE 2 40 GO...

Page 220: ...O M 345 IF S J LET J 570 Number of pairs to RNO N J J J 590 IF A S GOTO N GO TO 360 640 be regiotered 350 FOR J 0TO N J 600 CLEAR 0 360 CLS PR JNT 6Hl INPUT ll F N M E p J MORY N OJM 370 INPUT Y N l J J N J J a A GOTO 390 620 JNPUT 11 F N ME R 380 ENO MORY J Sequential Random 390 IF A Y J A l s N JGOT O 530 ENO Extraction Flag 370 fi40 PR1NT 11 F N ME T 400 l F AS Y GOTO MORY N u 420 650 PR JNT ll...

Page 221: ...All and more about Sharp PC 1500 at http www PC 1500 info Do not sale this PDF ...

Page 222: ...All and more about Sharp PC 1500 at http www PC 1500 info SHARP CORPORATION OSAKA JAPAN Do not sale this PDF Pfintcd In Jap0t 2G080 TtAANE 022CCZZ S ...