STEP 5 Operations
S5-95F
The result of the arithmetic operation is available in ACCU 1 for further processing. The contents of
ACCU 2 are not affected.
Explanation
STL
L
IW 92
L
KH 00FF
AW
T
QW 82
Load input word IW92 into ACCU 1.
Load a constant into ACCU 1. The previous contents of ACCU 1 are shifted
to ACCU 2.
Combine the contents of both accumulators bit by bit through logic AND.
Transfer the resulting contents from ACCU 1 to output word QW82.
Numeric Example
ACCU 2
ACCU 1
ACCU 1
1 0 0 1 1 1 0 0
AND
Result
0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
15
0
0 0 0 0 0 0 0 0
0 1 1 1 0 0 0 1 1 0 0 1 1 1 0 0
KH 00FF
IW92
Set the 8 high-order bits in input
word IW92 to "0".
Compare both words bit by bit. If
corresponding bits are both “1”, the
result bit is set to "1".
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
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8-44
EWA 4NEB 812 6210-02