Calculation of air ducts
Example 2: IPS800, 459 kW (625 hp)
Calculation of areas for one 459 kW engine with an
unlimited airflow and an outside temperature of +30 °C
(+86°F).
Air consumption:
The following is obtained for
each
engine:
Area for engine air consumption: 1.9 × 459 = 872
cm
2
(135.5 sq.in)
No corrections according to the
Coefficient of bends
and
Correction factor
tables The area 874 cm² (135.5
sq.in) gives a duct diameter of 267 mm (10.5") for each
engine (2√(area/π)).
Multiply by the number of engines to calculate the area
of the engine compartment inlet duct.
Ventilation:
1
Air intake:
Area = 1.65 × 459 = 757 cm
2
(117.6
sq.in). This gives a diameter of 304 mm (12.0") for
a single engine.
2
Air outlet:
Area = 1.65 × 459 = 757 cm
2
(117.6
sq.in). This gives a diameter of 304 mm (12.0") for
a single engine.
3
Extraction fan capacities:
0.07 × 459 = 32.1
m
3
/min (1091 ft
3
/min).
4 Multiply each sum by the number of engines to cal-
culate the area and fan capacity for a common
engine compartment.
Arrangement and Planning, Engine Room
47704162 10-2014 © AB VOLVO PENTA
27
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